Webcalc Ii

After performing the test, a chi square value of 126.58 was determined. With a degrees of freedom value of 4, this constituted a p value of 2.101644 x 10-26. With an alpha level of .01, the null hypothesis was rejected.

The numbers given in the case were as follows: assumed population standard deviation is equal to .21, sample size is equal to 30 and the test value of the mean was 12. They also stated the two hypotheses to be tested: the null hypothesis that the population is equal to 12 and the alternative hypothesis that the mean is not equal to 12.

The underweight experimental group will be measured against the underweight control group and likewise for the two overweight groups. Potential outcomes are that will either prove or disprove the hypothesis are:

The null hypotheses states that there is no statistically significant differences or relationships between the independent variable and the dependent variable within a study.

Since the P-value is less than the level of significance rejects the null hypothesis (Mirabella, 2011). In conclusion, reject the null hypothesis and conclude a difference in the mean GPA’s of the students from the Bachelors to the Master’s programs (Mirabella, 2011).

The author uses the statistical package (SPSS v.16) in order to compare and analyze data of the control and the experimental groups. The statistical tests described in the Method section or Data analysis paragraph but in the Result section.

In our conclusion we dismiss the null hypothesis on the grounds that we are expressing that the sample statistic is sufficiently not the

It was hypothesized that the mean of ¡¥Low¡¦ group would be lower than ¡¥Accurate¡¦ group as participants filled in the questionnaire, they were given example of lower (50%) figure. They believed that the examples

A. Use the five-step p-value approach to hypothesis testing and a 0.05 level of significance to determine whether the proportion of full-time students at Miami University is different that the national norm of 0.46.

The results shown are the average of 10 different experiments ± SEM. (*) Indicates significant difference regarding to control group p ≤ 0.05 by Student “t” test.

H1/HA – Alternative Hypothesis: a statement you want to prove (E.g Average is not 50)

Hypothesis testing is the process in which an analyst may test a statistical hypothesis. The methodology used by the analyst is based on the nature of the data used and the main goals of the analysis. The main goal in this is to either reject or accept the null hypothesis. Through testing, results will show that someone who may prove one answer, may not mean that answer is actually correct, for there may be many factors that may change the outcome. For this reason is why researchers the five or one percent probability rates.

The null hypothesis is a statement that explains there is no relationship between two variables (Salkind, 2013). Using the

This is a quantitative research because I compared percentages to determine if there was or not a noticeable difference between the average of the first and second test

took a sample of the entire MBA population and surveyed the GPA scores of 100 men and 100 women. A sample will infer the truth regarding the population (Mirabella, 2011). They used a hypothesis test for two independent samples due to the men and women were not dependent of each other. They started with conducting a t-test for the independent mean for both men and women to determine if a significant difference exists. Women had a mean average GPA of 3.327 with a standard deviation of 0.301. Men had a mean GPA average of 3.516 with a standard deviation of 0.287. Furthermore, once the mean GPA was figured for both men and women they must decide if this is a two-tailed, upper-tailed, or a one-tailed test. In this case, it is a two-tailed test, which means they were testing to see if a difference exists between men and women and their GPAs. Basically, you are testing to see if the sample mean is different from the hypothesized value (Mirabella, 2011). The hypothesis would be written as: Ho:The mean MBA GPA of women equals that of men and Ha (alternate hypothesis): The mean MBA GPA of women does not equal that of men. So in this the p-value, which according to Bethel University (2010) stands for probability is 0.0000, which is less than the 0.05 significance level; therefore the null hypothesis, which according to Bethel University (2010) is the statement that is just accepted in the absence of evidence, is rejected and they can conclude that the mean MBA GPA is