What factors affect the rate of the decomposition of hydrogen peroxide with a fixed mass of catalyst?

This investigation will be carried out to investigate the rate of reaction of the enzyme catalase on the substrate hydrogen peroxide.

The purpose of this experiment was to simply measure oxygen production rates released from decomposed hydrogen peroxide under different conditions (concentration of enzymes, temperature, and PH level).

Introduction: Chemical reactions are dependent upon two factors: temperature and concentrations of substance. We can monitor the rate at which a chemical decomposes or the rate at which a chemical substance appears. In this experiment we will be measuring the rate of decomposition of hydrogen dioxide with the following reaction:

σAB = 0.3 × 0.07 × 0.14 + 0.4 × 0.06 × (−0.04) + 0.3 × (−0.08) × 0.08 − 0.021 × 0.05

I found this information by taking the Z score and looking at the Z table under the number curve, located in appendix of my textbook.

Please enter the numbers here so that I know that you know how to read the SPSS output. Please paste your SPSS output right here where it belongs.

Rounded to the closest hundreth, the standard deviation for the set is approximately 19.52. Juxtaposed

o 2.37, 2.38, 2.44, 2.46, 2.54, 2.64, 2.68, 2.79, 2.85, 2.89, 2.93, 2.94, 2.106, and 2.108

The chemical hydrogen peroxide(H₂O₂) is broken down by the enzyme catalase. Hydrogen peroxide is a byproduct formed in cellular reactions that, if not broken down, could inflict severe damage to the cell. Catalase is an enzyme that breaks down hydrogen peroxide in to water and oxygen. How efficient and strong the enzymes reaction to break down H₂O₂ determines largely on temperature and pH level. An enzyme only functions within a set pH and temperature range. Beyond that it becomes denatured, rendering it useless. The purpose of this lab is to determine at which temperature and pH level the enzyme catalase reacts best. Catalase in chicken and beef livers will be used to do the lab because enzymes still function after death as long as they are kept refrigerated at a low temperature.

0 7 188 0.085 1,067 0.48 207 236 — 417 300 2.2 0.4 59.3 10.1 0.24 64.4 1,241 539 2.5 4,026 97,000 625 17 21 5 20 — 1,065 642 10,643 69

2.52 0.63 49.19 3.50 74.31 39.83 69.86 96.97 5.34 1.46 0.65 0.57 5.73 1.47 35.22% 13.06% 7.01% 12.42% 29.41%

The presence of catalyst will cause hydrogen peroxide to break down into water and oxygen. The increase in the pH of the substrate will cause the increase in the rate of reaction. It will optimize at pH 7 and will diminish/moderate after pH 9.

6 95 111 135 155 160 114 55 33 41 92 91 91 61 67 118 136 131 94 26 11 8

What are the effects of different temperatures on the decomposition of Hydrogen Peroxide with the Enzyme Catalase. Different enzymes work best at different optimal temperatures, and with this experiment we hope to discover which temperatures are unideal for Catalase. The substrate is H2O2 which binds to the active site of the enzyme Catalase. The reaction in question is as written below:

Min 3.2x1 + 2.2x2 + 4.2x3 + 3.9x4 + 1.2x5 + 0.3x6 + 2.1x7 + 3.1x8 + 4.4x9 + 2.7x10 + 4.7x11 + 3.4x12 + 2.1x13 + 2.5x14 + 6.0x15 + 5.2x16 + 5.4x17 + 4.5x18 + 6.0x19 + 3.3x20 + 2.7x21 + 5.4x22 + 3.3x23 + 2.4x24 + 0.3x25 +0.7x26 + 3.5x27