The important thing is to never stop questioning. In science you must question everything and work to find the answer.The definition of the speed of something in a given direction. So when a car is moving north how fast it's moving would be its velocity. When the mass of an object is changed it can change the velocity. Mass is the amount an object weighs.In this experiment I took the mass of carts and changed them to observe their change in velocity.s. The law of conservation of momentum requires that the total momentum in the system must remain the same, or be conserved, even though mass or velocities of moving objects in a system may change. If the total mass of two colliding carts is increased, then the final velocity of the carts decrease? …show more content…
a) Click on the reset button. Adjust the glider masses back to 0.5 kg. Reposition the gliders with G1 on the left end of the track, and G2 on the right end, since both gliders will have an initial velocity moving toward each other for the collision. The exact position of each is not important, as long as they can collide near the middle. b) Record the masses of G1 and G2 in Table D. Calculate and record the combined mass of the gliders as well. c) Set the velocities to 3.0 m/s for G1, and –3.0 m/s for G2. Record the initial velocity and momentum of each glider in Table D as well. d) Press play to run the trial. After the collision, press pause to record velocity and momentum data for the combined gliders in Table D. e) Run a second trial. Click the reset button and change the mass of G2 to 0.8, and keep the other parameters the same. Record masses, velocities, and momentums as you did in Steps 3b–c, this time in Table E. Run the simulation, pausing after the collision to record postcollision velocity and momentum of the gliders in Table E. f) Repeat Step 3e to run a third trial where the mass of G2 is increased to 1.2 kg. Record masses, velocities, and momentum both before and after the collision in Table F. Step 4: Compare values for momentum. a) In each Table, find the momentum for each glider prior to the collision and for the combined mass after the collision. Momentum is calculated by using the …show more content…
Both carts can have the same mass and same velocity, but after the collision will have a slower velocity. Even after the collision the carts will have a velocity but their directions will have changed. When the carts change direction the velocities will change and the cart with the least amount of mass will have the greatest velocity. If one cart is moving faster in the beginning the one with the least amount of velocity will go backwards faster. Clearly, the velocity and mass of the cart affects the
In the first experiment, “ How does mass affect your game?” it shows that the data on “Ball- Mass 3” that the 10 pound bowling ball had the highest kinetic energy of 27(J), the greatest velocity (m/s) of 3.42, and in average it produced 4 bowling points. According to the data, on “ Ball- Mass 1” the 11 pound ball got an average velocity (m/s) of 3.14, the kinetic energy of 24 (J), and the average bowling points of 3. On the other hand, the evidence shows that the 12 pound bowling ball in “ Ball- Mass 2” has the velocity (m/s) of 3.12, the kinetic energy of 23 (J), and the average bowling points of 4 . Concluding that in my Game 1 the velocity of the masses of the bowling balls decreased when the bowling balls were heavier and that the kinetic energy was lower as the mass increased in the bowling balls.
VEHICLE ONE, WAS HEADED EAST ON W. CLUB BLVD WHEN IT WAS STRUCK ON THE REAR BUMPER BY THE FRONT BUMPER OF VEHICLE TWO, WHICH WAS HEADED EAST ON W. CLUB BLVD.
15) A cart starts from rest and accelerates at 4.0 m/s2 for 5.0 s, then maintain that velocity for 10 s, and then decelerates at the rate of 2.0 m/s2 for 4.0 s. What is the final speed of the car?
1) Once the simulation opens, click on ‘Show Both’ for Velocity and Acceleration at the top of the page. Now click and drag the red ball around the screen. Make 3 observations about the blue and green arrows (also called vectors) as you drag the ball around.
3. Explain whether, during a trip, a car’s instantaneous speed (movement of an object at a specific instant) can ever be greater than its average speed.
In Lab 6, we will exploring the conversation of mechanical energy. In this experiment we will be using various tools and instruments of measurement such as an air track, a glider, a photogate and an interface box. Because we are creating an isolated system, the total mechanical energy is conserved where gravitational kinetic energy is transferred to kinetic energy. In this experiment we can see the conservation of energy when the glider on the air track is pulled by the force of gravity acting upon the weight of the falling mass. We are able to neglect friction due to the presence of the air cushion which reduces the friction acting on the glider.
The velocity for cart 1 after collision is 0.203m/s and cart 2 after collision is 0.199m/s. Since, kinetic energy is directly proportional to the squared velocity, you can see the lost of kinetic energy in table 1. The sum of kinetic energy shown in table 1, before collision is 0.059joules, while the sum of kinetic energy after collision is 0.021joules. This graph shows an lost of approximately 0.03joules of kinetic energy.
Newton’s first law, which states: “An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction
These principles include conservation of energy, conservation of momentum, and ideas about forces that are vital in the production of any engineering device. When one object hits another in a Rube Goldberg machine, this is an example of the conservation of momentum occurring. Conservation of momentum says momentum is neither created nor destroyed, it only moves from one object to another. This is easiest to see when a ball bearing is used in a Rube Goldberg device, because ball bearings or marbles hit each other cleanly, and transfer the momentum in an elastic, clear way.
Because the smaller car has a smaller mass, you will require less kinetic energy to stop it compared to the larger car which requires more kinetic energy because of its larger mass.
I chose to find this out because I like working with wood. My hypothesis is that the oak wood will win because of the weight. The weight of the wood will make it go fast because of the downward momentum.
Momentum and energy are conserved as the numbers are equal before and after the collision.
Even though in this scenario the body mass and body segment dimensions of both players were the same and both players took off with the same vertical and horizontal velocity of their CoG, Player B redistributed her body mass about the CoG which
Newton’s laws of motion are three physical laws that describe the connection between a body and the different forces acting upon it, as well as its motion in response to those forces. Isaac Newton developed Galileo’s ideas further and developed three law of motions. Newton’s First Law of Motion states that an object at rest with remain this way unless if it affected by a force. Also if an object that is moving will continue at the same speed as well as the same direction until an unbalanced force acts upon it. An example of unbalance force is when a scooter is being driven, the friction and air resistance is going at it, the weight of the scooter is keeping the weight on the ground, the reaction force is going up and the thrust of the scooter going forward. The force’s tendency to resist any change in motion is called an object’s inertia. Newton’s Second Law of Motion states that an object will keep on accelerating in the direction of an unbalance force acting upon it. The mass of the object and the size of the force acting depends upon the size of the acceleration., F_net=m x a, is the formula to work out the total amount of force acting upon an object. This formula can be
HYPOTHESIS: Without the effects of friction the momentum will be conserved in the isolated system. In all three experiments the momentum before the interaction will equal the momentum after the interaction.