Essay on note

How can you explain to the farmer that it is possible to draw these two different conclusions from the same data? (2 marks) (f) Calculate the p-value for the hypothesis tests in parts (b) and (d). How might knowing this value improve the explanation given to the farmer in part (e)? (4 marks) Hint: Think about the definition of the p-value and how this might let you provide a more concise and specific response to the farmer’s concerns

Customers make demands on the market by routinely expressing their desire for “more”. This has been called “seeking a bigger and better deal”. The demand is for more value, and more options. As they search the marketplace for its offerings, customers are often pleased to see new suppliers. They consider the new offerings, and make decisions about changing their purchasing habits.

15 In testing the hypotheses: H0 β1 ’ 0: vs. H1: β 1 ≠ 0 , the following statistics are available: n = 10, b0 = 1.8, b1 = 2.45, and Sb1= 1.20. The value of the test statistic is:

The null hypothesis is rejected since the p-value is below the significance level of 0.05.

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The Null Hypothesis for this test was Ho: u1- u2 = 0. Dr. Williams Found that the t-value = 0.98603, the p-value = 0.328213, and that p < 0.05. This means his results were not significant at a 0.05 level. Therefore, we fail to reject the null. Dr. Williams can conclude there is no difference between the scores of his two Intro Psych. classes.

Since P value is 0.049 which less than o.o5, the null hypothesis is rejected. The sample supports the alternative hypothesis that the mixing rate of the machine is less than 5 gallons per minute.

So the p-value for this test is 0.006. Which is smaller than the significance level 0.05, as a result I am rejecting the null hypothesis based on the p-value approach as well.

Conclusion : Reject the null hypothesis. The sample provide enough evidence to support the claim that mean is significantly different from 12 .

In this case, the null hypothesis has been proven and accepted. Keep in mind that the null hypothesis “predicts that the

Initially, customer X was ordering a specific type of Torsion Rod (8mm) produced by high grade Aluminum wire. Customer Y has been purchasing Steel wire Torsion rod (8mm). Wire length is 1inch. The Production team was able to meet the demands by running these separate orders in a single machine with wire straightening and cutting operation. The chamfering operation is done in separate machine. In recent past, customer X had ordered for Steel torsion rods too. The order quantity is large which requires Peterson Spring to purchase new wire straightening and cutting operation machine as well as Chamfer Operation. On the other hand, customer Y has given a new order. There is an existing order with chamfering operation and the new order with just cutting operation. The Production team found it difficult meeting the work order with current resources. The Production Team raised this issue to senior management which might create a bad reputation if failing to meet the demands of customer and delivering order on specified date. The Production Team met with Senior Management and funds were sanctioned to purchase a chamfering machine to support existing production of SUSPA Torsion rods. It is expected that Peterson Spring will be attracting new customers and few more orders of higher quantity from existing customers in next few months to come. There has never been any quality issue or reject from

Advanced Wire’s product was of the highest attainable quality, in regards to the engineering department’s opinion.

The null hypothesis suggests that there is no difference between the means of the three samples, while the claim in the alternative hypothesis suggests that at least one mean is different.

that it has been using are working very well for them and it has generated a solid trend of