Question

Asked Nov 25, 2019

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You have been hired to design a family-friendly see-saw. Your design will feature a uniform board (mass *M* = 7 kg, length *L* = 7 m) that can be moved so that the pivot is a distance *d* from the center of the board. This will allow riders to achieve static equilibrium even if they are of different mass, as most people are. You have decided that each rider will be positioned so that his/her center of mass will be a distance *x _{offset}* = 11 cm from the end of the board when seated as shown.

You have selected a child of mass

Determine the magnitude of the force exerted on the pivot point by the see-saw in N.

Step 1

Given data:

Mass of the board, M = 7 kg.

Length of the board, L = 7 m

*X _{offset}*

Mass of the child, m_{1} = 29 kg

Mass of the adult, m_{2} = 3 x 29 = 87 kg

Step 2

From fig.

X_{1} = L / 2 - *X _{offset} – d = 7 /2 – 0.11 – d = 3.39 - d *

X_{2 }*= L /2 + d - X _{offset} = 7 /2 + 0.11 – d = 3.61 - d*

Step 3

Taking moment about the pivot:

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