Homework Help is Here – Start Your Trial Now!
Math
Calculus
. y = 2 In(3x² – 1) 2 (In(3x2 – 2)) (3x² – 1) dx dx dx dy = 2. dx 1 6x In(3x² – 1) dy 12x dx Зx2 — 1 2. y = x(In x)³ dy := x-(In x)³ + (ln x)³x d d dx dy : = x • 3(In x)² + (In x)³(1) dx dx dy 3(In x)² + (In x)³ dx dy (In x)²(3 + In x) dx 3. g(x) : d sec x(2 sin x) – (2 sin x) (sec x) secx 2 sin z (kindly refer to your trigonometric identities) gʻ(x) (2 sin x)² 2 sec x cos x – 2 sin x sec x tan x g'(x) = (2 sin x)² 2(1) – 2(tan²x) (2 sin x)² gʻ(x) = %3D

. y = 2 In(3x² – 1) 2 (In(3x2 – 2)) (3x² – 1) dx dx dx dy = 2. dx 1 6x In(3x² – 1) dy 12x dx Зx2 — 1 2. y = x(In x)³ dy := x-(In x)³ + (ln x)³x d d dx dy : = x • 3(In x)² + (In x)³(1) dx dx dy 3(In x)² + (In x)³ dx dy (In x)²(3 + In x) dx 3. g(x) : d sec x(2 sin x) – (2 sin x) (sec x) secx 2 sin z (kindly refer to your trigonometric identities) gʻ(x) (2 sin x)² 2 sec x cos x – 2 sin x sec x tan x g'(x) = (2 sin x)² 2(1) – 2(tan²x) (2 sin x)² gʻ(x) = %3D

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
See similar textbooks
icon
Related questions
Topic Video
Question

II. ERROR IDENTIFICATION. Identify the errors present in the given solutions. Put an X mark on the spaces provided beside the error, then write the correct solution.

Answer Problem 1 & 3

1. у%3D2 In(3x? — 1) dy In(3x² – 2)]- (3x² – 1) dx dx dx dy = 2 . dx 1 6x In(3x² – 1) dy 12x dx Зx2 — 1 2. у %3D х (In x)3 dy d d = x- (In x)³ + (ln x)³- dx dx dx dy = x · 3(In x)? + (In x)³(1) dx dy 3(In x)² + (In x)³ dx dy = (In x)²(3 + In x) dx d sec x (2 sin x) – (2 sin x) (sec x) (2 sin x)² d sec x 3. g(x) = 2 sin z (kindly refer to your trigonometric identities) gʻ(x) = 2 sec x cos x – 2 sin x sec x tan x gʻ(x) = (2 sin x)2 2(1) – 2(tan²x) (2 sin x)² 2(1 – tan²x) 2sin²x 1- tan?x gʻ(x) = gʻ(x) = gʻ(x) = 2sin?x
Transcribed Image Text:1. у%3D2 In(3x? — 1) dy In(3x² – 2)]- (3x² – 1) dx dx dx dy = 2 . dx 1 6x In(3x² – 1) dy 12x dx Зx2 — 1 2. у %3D х (In x)3 dy d d = x- (In x)³ + (ln x)³- dx dx dx dy = x · 3(In x)? + (In x)³(1) dx dy 3(In x)² + (In x)³ dx dy = (In x)²(3 + In x) dx d sec x (2 sin x) – (2 sin x) (sec x) (2 sin x)² d sec x 3. g(x) = 2 sin z (kindly refer to your trigonometric identities) gʻ(x) = 2 sec x cos x – 2 sin x sec x tan x gʻ(x) = (2 sin x)2 2(1) – 2(tan²x) (2 sin x)² 2(1 – tan²x) 2sin²x 1- tan?x gʻ(x) = gʻ(x) = gʻ(x) = 2sin?x
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Optimization
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
SEE MORE TEXTBOOKS