Question
Asked Oct 15, 2019
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0<x<2pi

F(x)=-4cosx

G(x)=2cosx+3

Solve for f(x)>g(x) on [0,2pi]. write the answer using interval notation. The, shade the region bounded by the graphs of f and g between the points of intersection. 

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Expert Answer

Step 1

Refer to the question, we need to solve the for x on [0,2pi] , F(x)>G(x)  and then shade the region bounded by the graphs of f and g between the points of intersection.

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F(x)=-4cosr G(x) 2cos x3 xe[0.27]

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Step 2

Then solve F(x)>g(x) to get the value of x as,

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-4 cosx 2cos x+ 3 Let cosx =u -4u > 2u+3 1 2 1 cos.x 2

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Step 3

Now use the following results for...

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For cos(x)a,if -1<as1 Then cos (a)2n <x < 27 - cosa+27n Now +27n< x< 27-cos 2 +2Tm 2 cos 27 4л -аnd 2л - сos 3 As cos 2 so. 2T 47T <x < 3 3 2л 4т хе 3 3

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Tagged in

Math

Trigonometry