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Question

Consider the image below of a wheel that pivots about its center.

Force 1 has size 176 N and acts 1.8 m from the center.  The angle shown is 36 degrees.

Force 2 has size 111 N and acts 0.7 m from the center.  The angle shown is 30 degrees.

Taking counterclockwise to be positive, calculate the net torque on the wheel, in N m.

(Please answer to the fourth decimal place - i.e 14.3225)

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Expert Solution
Step 1

Given Data:

  • First force, F1=176 N.
  • Second force, F2=111 N.
  • First distance, r1=1.8 m. 
  • Second distance, r2=0.7 m.
  • First angle, θ1=36°.
  • Second angle, θ2=30°.
Step 2

Torque acting on wheel is given by:

τ=r×Fτ=rFsinθ

First Torque:

τ1=1.8 m×176 N×sin36°τ1=186.2104 N·m

Second Torque:

τ2=0.7 m×111 N×sin90°-30°τ2=67.2902 N·m

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