-1 5 3 -6 3 2 -1 1 -5 -3 6, 5.

Q: :). -5 -3 -7 1 17 - 70 -5 9. 10 35 -5

A:

Q: -(5-3)²+(8+2)-3(4-1)²=

A:

Q: 1. 2х - 2х2 %3 7 2. 6-2х2 — 6х бх 3. (х+5) (х+4) 3D0

A: As per Bartleby guideline rules I am answering only top 3 questions.

Q: 10 8. A 10 -8 -6 -2 0 2 6 8 10 -2 -4 -8 -10 (7, -5) 2 (-1 5) 6. 4.

A: doing reflection and shifting

Q: 5 4 3 2 -6 -5 -4 -3 -2 -1 -1 I 2 3 4 5 6 -2 -3 -5 |-6+

A: Consider the following figure We have to find the range of the given function.

Q: 6+ 5. 1- -5 -3 -2 1 2 3 5 -1 -2+ -4 -5- 3. 2. 3.

A:

Q: 6- 5 3. 2+ -7-6 5 -4-32 2 3 4 5 6 7 4 -5- -6-

A: Solution of this question is

Q: 10 8- -7- 9- -5- 1. -3 -2 -8 -6 -5 -4 -3 -2 3. 4. 9.

A:

Q: -4 3 2 -1 -4 -3 -2 -1 1 2 4 -1 -2 -3 --4 3.

A: To find f(2) using the given graph.

Q: -4 2- -3 -2 -1 1 2 4 5 --1 --2 --3 -4 3. 3.

A:

Q: 7+ 6- 5- (2, 5) 4- |(-4, 4) 3+ 2

A: Given points are -4,4 and 2,5find the center and radius of the circle.

Q: 10- 6- 4- 2 10 8 -6 4 2 4 8 10 4- -6- -8- -10-

A: Consider the provided graph, First we find the equation of the line.

Q: 6 4 -3-- 2-- 1 -1 1 2 3 4 8 --1 LO

A: Given that graph of f(x) To find absolute minimum value of funnction

Q: 10 -8- -6- -2 -10 -8 -6 -2 6 10 -2- --6- -8 -10 |으

A:

Q: 3) (5 - 2) + ) – 3) (2+9 - (-2 11

A:

Q: 6 5 3 1 + -4 -2 -1 3 4 5 -2 -3 - -4 2. + 2.

A: Let us use Newton Algorithm to find the polynomial. The curve given passes through the points…

Q: -8- 7 -6 3 2- 4 5 6 7 -4 -3 -2 -1 0 -1- -8 -7 -6 -5 2 -3 4- -5 -6- -7- --8- 3- 2.

A: The equation of a circle with center at (a,b) and radius r is given by, x-a2+y-b2=r2

Q: 2 0 -4 6| 4 1 0 2 6 -1 -3 8 9 1

A:

Q: ++++> -4 -2 0 2 4 6 8 10 12 14 - 12 4

A: The given inequality, n4≤0 or 2+n≥12

Q: 4- 3+ -3 -1 1 2 -1+ -2- +3- -4- -5 3 of 4

A:

Q: ((-25) + (-5)) – (-10) - 16 + (6 + 2) )-(8-)-a-(-) ( (-8) + 8 + (–1)³

A:

Q: 10- 5- -10 -5 5 10 -5 -10F

A:

Q: 4+ 2 9- -4 -2 2 4 6 2 -4- 6+

A:

Q: -10 -8 -4 -2 6. 8. 10 -2 -4 -6 -8 -10 9.

A:

Q: 10 -8- -6- -2 -10 -8 -6 -2 6 8 10 -2 --6-

A:

Q: 3 2 -5 4 3 2 5 6 -1 -2 -5 to

A:

Q: 1 1 -2 16. Л 3 3, А — -1 1 0 1 -1

A:

Q: -3 +2.2а° + с -3 2.24 + с 3 +2.24 + с 6- +0.824 + с -3 .5+ 2.23 + с 4

A:

Q: 2- .....*. -5 -4 -3 -2 A (-2, 2) C (2, -2) В (4, 3) D (-4, 0)

A: From above shaded region it is clear that

Q: ((-2, 1) = 3 NWAGO 5- 4+ 3 2- 1+ -6-5-4-3-2-1₁ 0 1 2 3 4 5 1 +2+ -3+ 4 L

A:

Q: What is the standard form of the equation of the circle?

A: Center of the circle is =(h,k)= (2,-8) Radius of the circle = r = 1

Q: ) 4-(-8) – (-2) + (-10) – 10 – 5)

A:

Q: -3 -3 2 -5 9 -3 -2 2 = 4X – 3 8 - -7 -8

A:

Q: 2- 10 -9 -8 -7 -6 -5 -4 -3 -6- 4. on

A: To find an equation for the given graph and write them in slope intercept form. Solution: Equation…

Q: 3 由 -9-8-7--5-4-3-2-1 1 2 345 6 -1 -2 7 8 9 -3 -4 -5

A: We have to find the discontinuous points.

Q: -7-6-5-4-3-2- 6 5 4 3 -2 -5. -6. H 1 2 3 4 5 6 7

A:

Q: (-5) + 4 – 1+ 4- (-21) * (-7)) ova

A: Simplification

Q: -5-4 -3 -2 - 1 2 -1 3 4 5 -2 -3 -4 -5

A: given graph, we have to find which equation best represents the relationship between x and y.

Q: Find the rank of the matrix

A:

Q: 5- 4 3 న్ -- /-3 -2 1 2 3 4 5 -2 -3

A:

Q: 5+ -5 -4-3 2 -1 2 3 4 5 -2 -3- -4 -5+ 3.

A:

Q: 1 -3 2 -3 -4 0 5 6

A: Given set of matrices is: M2×3ℝ=1-32-405,-3746-2-7,-2311-1-32 We have to check if the above set of 2…

Q: -2 3 -5 2 3 3 2 3 1 1 -4

A:

Q: |2y + 6| < 10 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10

A: Given:2y+6&lt;10

Q: 10- 8- 6- 4- 2- -8 -4 -2 10 2- 4- -6- 40

A: Draw a graph.

Q: 7- 4- 2 -8 -7 -6 -5 -4 -3 -2 -1 I 2 5 6 7 -2 -3 -4 -5 -7 6

A: here equation is given  by y=4ax^2 vertex at (3,-1) than  x=a(y-3)^2-1 now x intercept is (5,0) that…

Q: 4. 시4,-1) B(2.5) 5. Al-3. 7) B(4. .5)

A: Our Aim is to find the distance between two points given below:-(4) A(4,-1) and B(2,5)(5) A(-3,7)…

Q: 3.7 = 5.4x - 5.5

A:

Q: (-3.3) 7 6 5 4 3 2 (-3,2) 1 -6 -5 -4 -3 -2 -1 -2 -3 -4 -5 -6 -7 1 2 3 4 5 6 7 (2)

A: Given Data:- Here point (x,y) is unknown so we should find it.