1) A ball of mass, m = 2.50 kg, floats on a pool of fluid, L-1.00 m wide. It is attached to supports at either end of the pool by springs, as shown in Fig.-1. The left spring has a spring constant, A = 65.0 N/m, and equilibrium length, L1-0.600 m. The spring on the right has a spring constant, k2-75.0N/m, and equilibrium length, L20.800m L = 1.00 m ki, Li Figure 1 -A ball of mass, m = 2.50 kg, floats on a pool of fluid, L = 1.00 m wide. It is attached to supports at either end of the pool by springs. The left spring has a spring constant, A = 65.0 N/m, and equilibrium length, L1 = 0.600 m. The right spring has a spring constant. ka = 75.0 N/m, and equilibrium length, L2 = 0.800 m. (Not to scale.) a) The ball is initially at rest at position, x - d. It's then pulled to the center between the two supports at 0.500 m, and let go. How long after it's let go does it take to return to x- d? (Neglect the drag of the fluid.) Supposing we now consider that the fuld exerts a drag force on the ball of fD b 20.0kg/s. If the ball is again pulled to the center at aand let go, now how long does it take to return to the position, x = d? b) -bu, where c) In Part b, once the ball gets back to the position, x - d, what's the furthest it will get from r-d after that? d) Supposing the drag coefficient is changed to b = 40.0 kg/s. If the ball is again pulled to the center at and let go, now how long does it take to return to the position, x-d? 2 e) Going back to Part b with the drag coefficient given by b -20.0 kg/s, supposing the ball is initially at rest at x - d. But then it's driven with a driving force given by F (50.0N) cos [(8.00s) ]. After a long time has passed, how fast will the ball be traveling whenever it passes through the point where x?

In both cases shown in the diagram below, a block is floating at rest in a liquid. The liquids in the two beakers have the same density, that is, PA = PB. Both blocks have 55% of their volume below the surface, but the volumes of the blocks are not the same. Find the mass m2 in terms of V1, V2, and m1. Block 1 Block 2 mi m2 РА Рв Vị m2 = mị V, V2 m2 = mj Vị (V2–V1) (V2+V1), m2 = mj m2 = 0.55mị m2 = 0.45mị

Are the ships in the preceding question sucked together or pushed together? Explain.

In the figure below, containers of different shapes contain the same liquid. The difference in pressure between the depths of x and y is A B C X----- y----- greatest for the cylinder with the smallest diameter same for all containers greatest for the cylinder with the biggest diameter d

Helpppp

Model of maximum walking speed. A walking person is modelled as a mass m and its center of gravity rotates around a circle of radius l (leg+hip length) with a speed v. The leg touches the ground. The speed v of the walking person is at the top of the trajectory. Derive the maximum speed v that still allows contact with the ground. Express it in terms of the variables. Consider now that the system is submerged in a liquid. Model the effect of the liquid as a buoyant force that is x fraction of the weight force. Neglect moment of inertia and derive the new “walking speed” in terms of x and the variables. Neglect drag.