(1) A graph of current 1 (Amps) verses time t (s) is modelled below:- 1 = 8.7t ¹.3 t = a) So that the cables and charging system do not overload, the current must not exceed 180 A. Work out how long it takes to reach 180A 1.5/180 8.7 b) Determine the total charge after initial switch-on by using definite integration. Q=10.288.71¹.³dt 18.7.2.3 2.3 under = 10.28 seconds Q = t 1.3, 10.28 0 = fidt 0 8.7x10.282.3 2.3 = 804.22 N.B. The total charge passed on to a battery is represented by the area a graph of current against time.

University Physics Volume 2
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Chapter12: Sources Of Magnetic Fields
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Problem 32P: Two long, parallel wires are hung by cords of length 5.0 cm, as shown in the accompanying figure....
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Electrical & Electronic Engineering, Physics often use mathematical modelling to represent in theory real life situations. An example of this is a current against time graph where the area under the curve represents the amount of charge, or a velocity time graph where the area under the curve gives the distance travelled. can you check this question is it correct or not i need detailed answer of this 

(1) A graph of current I (Amps) verses time t (s) is modelled below:-
t =
Q =
1.5/180
8.7
under
a) So that the cables and charging system do not overload, the current
must not exceed 180 A. Work out how long it takes to reach 180A
Q = $10.288.7t¹.³dt
= 10.28 seconds
8.7 2.3
2.3
b) Determine the total charge after initial switch-on by using definite
integration.
1 = 8.7t
10.28
0
t
Q = fidt
0
1.3
2.3
8.7x10.282
2.3
= 804.22
N.B. The total charge passed on to a battery is represented by the area
a graph of current against time.
Transcribed Image Text:(1) A graph of current I (Amps) verses time t (s) is modelled below:- t = Q = 1.5/180 8.7 under a) So that the cables and charging system do not overload, the current must not exceed 180 A. Work out how long it takes to reach 180A Q = $10.288.7t¹.³dt = 10.28 seconds 8.7 2.3 2.3 b) Determine the total charge after initial switch-on by using definite integration. 1 = 8.7t 10.28 0 t Q = fidt 0 1.3 2.3 8.7x10.282 2.3 = 804.22 N.B. The total charge passed on to a battery is represented by the area a graph of current against time.
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