1 - tan2 x X 4. cos 2x 1 +tan2

Q: 2sinx-5sin.x-330 tanx+3 =3secx 2 sin 2x+1-0

A:

Q: (cos(4x))^2=___+____cos=(___x)

A: By double angle formula , we have By taking A=4x, we get

Q: 2 cos² x√4 tan x S tan² x dx

A:

Q: 2 cos^2 x-sin x -1=0

A: 2cos2x-sinx-1=0⇒1-sinx-2sin2x=0⇒sinx=-1, sinx=12⇒x=3π2+2πn, x=π6+2πn, x=5π6+2πn

Q: 1/1+cos x + 1/1-cos x=2csc^2 x

A: Please refer the attached image for complete solution.

Q: 2+tan x cos³ x

A:

Q: 15) tan-l –1 --1 V2 17) cos 2 1 19) tan- 1

A: Given: 16)  tan-1-1

Q: 2) sin- 0 4) cos 6) cos-1 | V3 8) tan 3 -1 -1 10) cos

A:

Q: 6sin2(x) - cos(x) - 5 = 0 for all solutions 0 ≤ x < 2π x = ???

A: Explanation of the solution is given below...

Q: 12) Solve: (tan x) (2cosx+1) = 0 %3D tan x = 0 2 cos x + 1 = 0 x = 0 2cos x = -1 m<x= 0 coS X = - m<…

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Q: 2 (tan²x + 1)√sin2x.dx= (tan², 0

A: Find your answer below

Q: 2 tan x sin 2x 6.) 1+tan² x

A:

Q: 7. cos 2x- cos x -2 = 0

A:

Q: Verify the identity.

A: 2cos⁻¹x = cos⁻¹(2x²-1) , 0 ≤ x ≤ 1 RHS = cos-1(2x2 - 1)Let cos-1(2x2 - 1) = AcosA = (2x² - 1)cosA +…

Q: cos 2x + 2 sin 2 x = _______

A: This question can be solved by applying the formula of cos2x cos2x=cos2x-sin2x

Q: Cos 3.x - cos 7x 53. sin 7x + sin 3.x cos tan 2r 54. sin = %3D

A: We can verify question no 53 as below

Q: -1 1- x² 1+x? Differentiate cos with respect to tan -1 2x 1- x2 '

A: Derivative of one function with respect to another function. Using substitutions to find derivative.

Q: -sin^2(x)=cos(2x) from [-pi, pi]

A:

Q: 3下 2 cos x 1-Sin x

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Q: *k) 1- (sinº x+cos x) = 3 sin² x cos²x

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Q: (2k + 1). True or False tan 0. cos 0 = sin 0 for any 0 + %3D

A: Given :            tan θ . cos θ = sin θ for any θ ≠ (2k + 1)π2.  To state true or fase.

Q: sin(2x) 1 Prove the following identity: cos(2x) - 1 - tan(x) sin(2x) %3D cos(2z) - 1

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Q: a. [CO²2 2 cos²x√4 tan x tan² x da

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Q: 2. 1-tan x w) cos2x 1+tan x |3|

A: Topic = Trigonometry

Q: Solve x 2x 2x 2π cos - ( 2² -1) + sin ~¹ ( 24₁ ) + tan - ( ²²₁ ) = ² COS 2 +1 x +1 3 -

A:

Q: 11) cos x csc X tan x - 1 11) 12) cos2x - sin2x = 1 - 2 sin²x 12)

A:

Q: Verify the identity. 6 cos(sin-1 x) = / 36 – 36x2 Let 0 = sin-1 x = sin 0 = x = X. Thus, 6 cos(sin-1…

A: use trigonometric identity  to verify it.

Q: 2 1-tan ² x 2 1+ tan² x 2 = cos²x - sin² x

A:

Q: what is the general solution for -1=2tan(x) + tan2(x)

A: Simple calculation of trigonometric ratio

Q: 1-Cos 2x 1+ Cos 2x ix) tan x=

A: Prove :

Q: 5) f(x) = tan [In{sin(15x - 30)}] %3D

A: For this problem we have to apply derivation to each term.

Q: ( tan( tan3x)dx Evaluate: cos²3x A -In |sec(tan3x)| + C 3 |cos(tan3x)|+C B © --n |sin(tan3x)|+c O…

A: Evaluate: I=∫tantan 3xcos2 3xdx

Q: Solve 2 tan" x-tan x-15=0 on the interval [0, z).

A:

Q: 1-cos2.x sin 2.x : tanx

A: Given- 1-cos2xsin2x : tanx To Simplify- The above expression. Formula Used- cos2x=1-2sin2x and…

Q: solve cos 2x - 2 sin x - cos^2 x = -3 on the interval x ∈ [o,2pi]

A:

Q: 4) Verify. cos²(x)[1 C. – tan²(x)] = cos(2x)

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Q: 2 2. (sin cos x) = sin 2x +1 2х +

A: The given identity

Q: cos 2x+1 = 1+ tan?x 2 cos4x

A:

Q: 2 sin 1 3 -1 cos tan 4

A:

Q: sin 0 13. Prove that 1 - = Csc 0(1 + cos 0). Cos 0

A:

Q: 1 - cos2 x/sin x

A: To simplify the expression.

Q: Find x where 0 ≤ x ≤ 2π. cos x - tan²x = 1

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Q: [((1-tan^2(x))/sec^2(x)]= cos(2x)

A: To prove that  [((1-tan^2(x))/sec^2(x)]= cos(2x)

Q: • tan°(x) Xp- cos“(x) 1 1 tan9

A:

Q: 2 sin2x – 3 = 3 cos x and 90° < x < 270°

A: Hello , thanks for your question as it is not clear mentioned that it is Sin2 x or sin 2x So we are…

Q: cos 2x 17. cos x-sin x

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: 10. Prove: cos²(x)-sin²(x) =sin² (x) 1-tan²(x)

A:

Q: x) - 0.5 cos(x)) on the

A: Given as, f(x)=e-x3.2sinx-0.5cosx in the interval [3, 4].