1.An aqueous solution of 0.150 M HBr (80.00 mL) is titrated with 0.060 M NaOH, as shown below.HBr (aq)NaOH (aq)NaBr (aq) + H20 (1)Calculate the pH of the HBr solution before any NaOH has been addedа.b. Calculate the pH of the mixture after 50.00 mL of 0.060 M NaOH have been added.Calculate the pH of the mixture after 140.00 mL of 0.060 M NaOH have been addedc.

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Asked Oct 22, 2019
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1.
An aqueous solution of 0.150 M HBr (80.00 mL) is titrated with 0.060 M NaOH, as shown below.
HBr (aq)NaOH (aq)NaBr (aq) + H20 (1)
Calculate the pH of the HBr solution before any NaOH has been added
а.
b. Calculate the pH of the mixture after 50.00 mL of 0.060 M NaOH have been added.
Calculate the pH of the mixture after 140.00 mL of 0.060 M NaOH have been added
c.
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1. An aqueous solution of 0.150 M HBr (80.00 mL) is titrated with 0.060 M NaOH, as shown below. HBr (aq)NaOH (aq)NaBr (aq) + H20 (1) Calculate the pH of the HBr solution before any NaOH has been added а. b. Calculate the pH of the mixture after 50.00 mL of 0.060 M NaOH have been added. Calculate the pH of the mixture after 140.00 mL of 0.060 M NaOH have been added c.

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Expert Answer

Step 1

Given,

0.150 M HBr is titrated with 0.060 M of NaOH.

pH is calculated by using following formula
pH log(H
The concentration of H is 0.150 M.
pH is calculated as follows,
pH log(H
pH log(0.150)
pH 0.82
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pH is calculated by using following formula pH log(H The concentration of H is 0.150 M. pH is calculated as follows, pH log(H pH log(0.150) pH 0.82

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Step 2

(b)  pH of the mixture has to be calculated after 50 ml of 0.060 M NaOH is added.

 

Number of moles...

Number of moles of HCl is calculated as follows,
Number of moles = Molarity xVolume
Number of moles 0.150 x0.08 L
Number of moles 0.012
Number of moles of NaOH is calculated as follows,
Number of moles= Molarity xVolume
Number of moles 0.060 x0.05 L
Number of moles 0.003
Moles of HCl remains 0.012 mol es - 0.003 moles
Moles of HCl remains 0.009 moles
Concentration is calculated as follows
mole
Concentration=.
volumein litre
0.009
Concentrati on
0.14L
Concentration=0.0643
pH is calculated as follows
pH log(H
pH log(0.0643)
pH 1.19
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Number of moles of HCl is calculated as follows, Number of moles = Molarity xVolume Number of moles 0.150 x0.08 L Number of moles 0.012 Number of moles of NaOH is calculated as follows, Number of moles= Molarity xVolume Number of moles 0.060 x0.05 L Number of moles 0.003 Moles of HCl remains 0.012 mol es - 0.003 moles Moles of HCl remains 0.009 moles Concentration is calculated as follows mole Concentration=. volumein litre 0.009 Concentrati on 0.14L Concentration=0.0643 pH is calculated as follows pH log(H pH log(0.0643) pH 1.19

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