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Asked Nov 13, 2019
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1. Define a random variable X as the proportion of time that a student spends on a certain test. Research suggests that the pdf of x is f(x) = (θ + 1)xθ , 0 ≤ x ≤ 1. For the parameter θ, we know θ > −1, but its exact value is still unknown. To estimate the parameter, a random sample of 10 students is obtained, and their proportions of time are: 0.92, 0.79, 0.90, 0.65, 0.86, 0.47, 0.73, 0.97, 0.94, 0.77. Find the Maximum Likelihood Estimator (MLE) of θ.

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Expert Answer

Step 1

Likelihood function:

The pdf is considered as f(x)=(θ+1)xθ.

The likelihood function of the distribution is:

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и S(4,*,0)-П(0+1)**] i=1 - (0+1) (җ*..*,)"

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Step 2

Log likelihood function:

Thus, the log likelihood function obtained by taking logarithm of the likelihood function is:

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0)]= In| (0+1) (x,, .] In f(x nln(01 n(x,x...x,) =nln(0+1)+In(x,) i-1

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Step 3

 Differentiating the log likelihood function with respect to θ:

The maximum likelihood estimator of θ is obtained by differentiating the log ...

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d In[f(x 0 2 de d 0 dθ η | nin (θ+1)+ ΟΣ 1n (x )| i=1 γη п ΣΠ(x)| θ+1 i-1 Pι п Σn (x) θ41 i-1 γη θ+1- PΟ Σn(x) i-1 δ. η -1 γη Σn(x) i-1

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