1. For a long solenoid, we discovered in a problem-of-the-day that B = µ,nl, where n isthe number of turns of wire per unit length along the solenoid.a. Use this fact and Faraday's Law of induction to calculate the inductance of a solenoidof cross-sectional area A and length I.b. If a solenoid has 10ʻ turns per meter, and is 5 cm in diameter and 50 cm long, and iscarrying a current of 10 A which is turned off in a time of 0.001 sec, what is the induced"back voltage" developed?

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Asked Dec 11, 2019
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1. For a long solenoid, we discovered in a problem-of-the-day that B = µ,nl, where n is
the number of turns of wire per unit length along the solenoid.
a. Use this fact and Faraday's Law of induction to calculate the inductance of a solenoid
of cross-sectional area A and length I.
b. If a solenoid has 10ʻ turns per meter, and is 5 cm in diameter and 50 cm long, and is
carrying a current of 10 A which is turned off in a time of 0.001 sec, what is the induced
"back voltage" developed?
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1. For a long solenoid, we discovered in a problem-of-the-day that B = µ,nl, where n is the number of turns of wire per unit length along the solenoid. a. Use this fact and Faraday's Law of induction to calculate the inductance of a solenoid of cross-sectional area A and length I. b. If a solenoid has 10ʻ turns per meter, and is 5 cm in diameter and 50 cm long, and is carrying a current of 10 A which is turned off in a time of 0.001 sec, what is the induced "back voltage" developed?

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Expert Answer

Step 1

(a)

Consider l be the length of the solenoid.

The expression for n in term of N, total number of terms are:

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N = nl

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Step 2

From faraday law of induction, the formula for the flux through a solenoid is:

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O = NBA = nlBA

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Step 3

Also, as mentioned in the question, the ex...

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В - Даnl

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Magnetic Effects of Current

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