1. The 12 kN m torque is applied to the free end of the 6-m steel shaft. The angle of rotationof the shaft is to be limited to 3°.(a) Find the diameter d of the smallest shaft that can be used.(b) What will be the maximum shear stress in the shaft? Use G = 83 GPa for steel.2. The compound shaft is attached to a rigid wall at each end. For the bronze segment AB,the diameter is 75 mm and G = 35 GPa. For the steel segment BC, the diameter is 50 mmand G = 83 GPa. Given that a = 2 m and b = 1.5 m, compute the largest torque T that canbe applied as shown in the figure if the maximum shear stress is limited to 60 MPa in thebronze and 80 MPa in the steel.75 mm50 mmABronzeBSteel 3. The two identical shafts, 1 and 2, are built into supports at their left ends. Gears mountedon their right ends engage a third gear that is attached to shaft 3. Determine the torquesin shafts 1 and 2 when the 500N -m torque is applied to shaft 3.40500 Nm80Dimensions in mm4. A 4-ft-long tube with the cross section shown in the figure is made of aluminum. Find thetorque that will cause a maximum shear stress of 10 000 psi. Use G = 4 x 106 psi for aluminum.+4 in. →0.04 in.0.08 in.´5. Two steel springs are arranged in series as shown. The upper spring has 36 turns of 100-mm-diameter wire on a mean radius of 350 mm. The lower spring consists of 24 turns of 75-mmdiameter wire on a mean radius of 245 mm. If the ultimate shearing stress in either springmust not exceed 692 MPa, (a) compute the maximum value of P and total elongation usingfactor of safety equal to 1.5. (b) What is the equivalent spring constant? Use G = 83 GPa.2 of 24 in.wwwww.-

you have posted multiple questions. As per the guidelines I am able to answer one question only. So…

1. The 12 kN m torque is applied to the free end of the 6-m steel shaft. The angle of rotation of the shaft is to be limited to 3°. (a) Find the diameter d of the smallest shaft that can be used. (b) What will be the maximum shear stress in the shaft? Use G = 83 GPa for steel.

1. The 12 kN m torque is applied to the free end of the 6-m steel shaft. The angle of rotation of the shaft is to be limited to 3°. (a) Find the diameter d of the smallest shaft that can be used. (b) What will be the maximum shear stress in the shaft? Use G = 83 GPa for steel.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter3: Torsion

Section: Chapter Questions

Problem 3.7.5P: The propeller shaft of a large ship has an outside diameter 18 in. and inside diameter 12 in,, as...

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Concept explainers

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.

Question

1. The 12 kN m torque is applied to the free end of the 6-m steel shaft. The angle of rotation
of the shaft is to be limited to 3°.
(a) Find the diameter d of the smallest shaft that can be used.
(b) What will be the maximum shear stress in the shaft? Use G = 83 GPa for steel.
2. The compound shaft is attached to a rigid wall at each end. For the bronze segment AB,
the diameter is 75 mm and G = 35 GPa. For the steel segment BC, the diameter is 50 mm
and G = 83 GPa. Given that a = 2 m and b = 1.5 m, compute the largest torque T that can
be applied as shown in the figure if the maximum shear stress is limited to 60 MPa in the
bronze and 80 MPa in the steel.
75 mm
50 mm
A
Bronze
B
Steel

3. The two identical shafts, 1 and 2, are built into supports at their left ends. Gears mounted
on their right ends engage a third gear that is attached to shaft 3. Determine the torques
in shafts 1 and 2 when the 500N -m torque is applied to shaft 3.
40
500 Nm
80
Dimensions in mm
4. A 4-ft-long tube with the cross section shown in the figure is made of aluminum. Find the
torque that will cause a maximum shear stress of 10 000 psi. Use G = 4 x 106 psi for aluminum.
+4 in. →
0.04 in.
0.08 in.´
5. Two steel springs are arranged in series as shown. The upper spring has 36 turns of 100-mm-
diameter wire on a mean radius of 350 mm. The lower spring consists of 24 turns of 75-mm
diameter wire on a mean radius of 245 mm. If the ultimate shearing stress in either spring
must not exceed 692 MPa, (a) compute the maximum value of P and total elongation using
factor of safety equal to 1.5. (b) What is the equivalent spring constant? Use G = 83 GPa.
2 of 2
4 in.
wwwww.-

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