1.000 mole of H2 gas and 1.000 mole of I2 vapor are introduced into a 5.00-liter sealed flask, The mixture is heated to a certain temperature and the following reaction occurs until equilibrium is established. (3)[H7 2 (3)I + (3)²H At equilibrium, the mixture is found to contain 1.580 mole of HI. (a) What are the concentrations of H2, I2 and HI at equilibrium? (b) Calculate the equilibrium constant K..

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.29P: 7-29 The following reaction was allowed to reach equilibrium at 25°C. Under each component is its...
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(3)HE + (3)0) z 6H+ (3)*HƆ
[CO][H, J
[o'HI['HO]
Calculating Equilibrium Constant
Example-1:
1.000 mole of H2 gas and 1.000 mole of I2 vapor are
introduced into a 5.00-liter sealed flask. The mixture is
heated to a certain temperature and the following reaction
occurs until equilibrium is established.
H2(g) + 2(g) 2 2HI(g)
At equilibrium, the mixture is found to contain 1.580 mole
of HI. (a) What are the concentrations of H2, I, and HI at
equilibrium? (b) Calculate the equilibrium constant K..
tmole
2 2H I
1 5
(2+28) mcle
te (-x)male +
(1-a)mile
242X
R H_ X I, )
2+2x =11680(
%3D
Transcribed Image Text:(3)HE + (3)0) z 6H+ (3)*HƆ [CO][H, J [o'HI['HO] Calculating Equilibrium Constant Example-1: 1.000 mole of H2 gas and 1.000 mole of I2 vapor are introduced into a 5.00-liter sealed flask. The mixture is heated to a certain temperature and the following reaction occurs until equilibrium is established. H2(g) + 2(g) 2 2HI(g) At equilibrium, the mixture is found to contain 1.580 mole of HI. (a) What are the concentrations of H2, I, and HI at equilibrium? (b) Calculate the equilibrium constant K.. tmole 2 2H I 1 5 (2+28) mcle te (-x)male + (1-a)mile 242X R H_ X I, ) 2+2x =11680( %3D
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