Question
Asked Apr 17, 2019

1.The [CoCl4]2- anion is intensely  blue colored and [CoCl6]4- is a lightly colored pink. explain breifly 

 

2.Why is the method of descending symmetry needed to derive an mo diagram for acetylene (ethyne), but not needed for diazene((NH)2)?

check_circleExpert Solution
Step 1

The color of the coordination complexes arises due to the transition of  electrons between different energy levels whose spacing is equal to the wavelength which is available in the visible light. There are many selection rules available for these electronic rules which will decide whether a particular transition will occur or not. One of them is the Laporte Selection rule which states that in an ion or a molecule which possess centre of symmetry , no transitions are allowed between orbitals having  same parity or we can say that the change in orbital quantum number .

Step 2

The geometry of the coordination complexes which are greatly affected by this rule are the complexes which are square planer or octahedral. However this rule is not applicable for the tetrahedral complexes as they there is no such centre of symmetry present in these complexes.

Sometimes some relaxations can occur for these selection rules by some mechanisms that allow electronic transitions to occur at low intensities. In case of octahedral complexes  some unsymmetrical vibrations may occur which has the ability to destroy the centre of symmetry of the complex and transitions are made allowed which would have been otherwise Laporte forbidden.

Step 3

No we know that an octahedral complex is the one in which the central metal atom is bonded to six ligands therefore the given complex ion CoCl64- is an octahedral complex ...

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