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- Calculate ΔSsys° (J/K) for the catalytic hydrogenation of acetylene to ethane: C2H2(g) + H2(g) → C2H4(g) Substance S° (J/K·mol) C2H2(g) 200.8 H2(g) 130.58 C2H4(g) 219.4An unknown compound of molecular formula C5H10O2, gives the HNMR data shown below. Which of the following structures is consistent with the data?What is the value in kJ/mol, of the lowest energy trnasition above? a.) 545 b.) 444 c.) 320 d.) 266
- Compound MM (g/mol) Volume Used (mL) d (g/mL) Weight Used (g) Moles Used Equivalence 9-anthracenemethanol 208.26 g g/mol N/A N/A 0.065 g (given) 0.0003 (rounded) 1 N-methylmaleimide 111.10 g/mol N/A N/A 0.104 g (given) 0.0003*3 = 0.0009 (rounded) 3 Diels-Alder Adduct/Product 319.4 g/mol N/A N/A 1 Please figure out the theoretical yield and moles of the product based on the table and image.Explain how heteroduplex formation is resolved during transformation?Most naturally occurring amino acids have chiral centers (the asymmetric a carbon atoms)that are named (S) by the Cahn–Ingold–Prelog convention (Section 5-3). The commonnaturally occurring form of cysteine has a chiral center that is named (R), however.(a) What is the relationship between (R)-cysteine and (S)-alanine? Do they have the oppositethree-dimensional configuration (as the names might suggest) or the same configuration?(b) (S)-Alanine is an l-amino acid (Figure 24-2). Is (R)-cysteine a d-amino acid or anl-amino acid?
- I need help calculating the binding constant and the free energy of binding Base Pairs – A & C 5 ml each Temperature, (°C) 25.00 [A], (M) 0.0441955 [C], (M) 0.0441955 [AC], (M) 0.00580452 Base Pairs – A & T 5 ml each Temperature, (°C) 25.00 [A], (M) 0.00163564 [T], (M) 0.00163564 [AT], (M) 0.0483644Iodide ion reacts with chloromethane to displace chlorideion in a common organic substitution reaction: I⁻+CH3Cl →CH3I+Cl⁻ (a) Draw a wedge-bond structure of chloroform and indicatethe most effective direction of Iattack.(b) The analogous reaction with 2-chlorobutane [FigureP16.107(b)] results in a major change in specific rotation asmeasured by polarimetry. Explain, showing a wedge-bondstructure of the product.(c) Under different conditions, 2-chlorobutane loses Clin arate-determining step to form a planar intermediate [FigureP16.107(c)]. This cationic species reacts with HI and then losesHto form a product that exhibits no optical activity. Explain,showing a wedge-bond structure.https://www.bartleby.com/solution-answer/chapter-83-problem-6p-organic-chemistry-9th-edition/9781305080485/when-an-unsymmetrical-alkene-such-as-propene-is-treated-with-n-bromosuc-cinimide-in-aqueous/b3feeb25-a92a-11e9-8385-02ee952b546e