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Asked Dec 11, 2019
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10. What is the energy released in this B+ nuclear reaction Al →Mg+e? (The atomic mass of 24 Al is 23.999939 u and that of 24 Mg is 23.985041 u)
x(14.4 MeV
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10. What is the energy released in this B+ nuclear reaction Al →Mg+e? (The atomic mass of 24 Al is 23.999939 u and that of 24 Mg is 23.985041 u) x(14.4 MeV

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Expert Answer

Step 1

Given,

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Mg +; e 24 Al 24 12 Al = 23.999939u 24 5 Mg = 23.98504 lu 12

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Step 2

Since the given equation is based on Einstein mass-energy theorem. The mass defect during the given reaction is calculated as follows,

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— (тмя + m,) Дт %3Dтд ?Mg *m, =0.000549u Am = 23.999939u – (23.98504lu + 0.000549u) Am = 23.999939u – 23.985590u Am = 0.014349u

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Step 3

Energy released can be ca...

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x 93 1 MeV ΔΕΔm ΔΕ0.014349u x 931 MeV ΔΕ-13.3589 19 MeV ΔΕ-13.36 MeV

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