Question
Asked Dec 19, 2019
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Consider the circuit shown in Figure P18.10. (a) Calculate
the equivalent resistance of the 10.0 - Ω and 5.00 - Ω resistors
connected in parallel. (b) Using the result of part (a),
calculate the combined resistance of the 10.0 - Ω, 5.00 - Ω, and
4.00 - Ω resistors. (c) Calculate the equivalent resistance of the
combined resistance found in part (b) and the parallel 3.00 - Ω
resistor. (d) Combine the equivalent resistance found in part
(c) with the 2.00 - Ω resistor. (e) Calculate the total current in
the circuit. (f) What is the voltage drop across the 2.00 - Ω resistor?
(g) Subtracting the result of part (f) from the battery voltage,
find the voltage across the 3.00 - Ω resistor. (h) Calculate
the current in the 3.00 - Ω resistor.

10.0 2
4.00 0
5.00 N
2.00 N
3.00 N
8.00 V
Figure P18.10
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10.0 2 4.00 0 5.00 N 2.00 N 3.00 N 8.00 V Figure P18.10

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Expert Answer

Step 1

Net Resistance in Series = R1 + R2


Net Resistance 1/Rnet = 1/R1 + 1/R2

Step 2

Part a :

10 ohms and 5 ohms are in parallel

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Rp 5 10 R, = 3.34ohm

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Step 3

Part b :

Rp1 is in series wit...

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Rsl= 4+3.34 =7.34 ohms

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Tagged in
SciencePhysics

Alternating Current

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