10.0m(10.0, 8.0)(4.0, 8.0)38.8.0f6.0t4.039.2.0t04.016.012.08.0Time (s)40.AFIGURE 2.23 Velocity versus time See Exercises 33 and 51.34.Figure 2.24 shows a plot of velocity versus time forobject in linear motion. (a) Compute the accelerationfor each phase of motion. (b) Describe how the objectmoves during the last time segment.. V41.an10.042.8.06.04.02.0t12.043.4.02.08.06.010.0-2.0-4.0-6.0-8.044-10.0-12.0Time (s)FIGURE 2.24 Velocity versus time See Exercises 34 and 55.4535. A car initially traveling to the right at a steady speedof 25 m/s for 5.0 s applies its brakes and slows at a con-stant rate of 5.0 m/s for 3.0 s. It then cnontinues travelingVelocity (m/s)Velocity (m/s)

Question
Asked Sep 9, 2019
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10.0
m
(10.0, 8.0)
(4.0, 8.0)
38.
8.0
f
6.0
t
4.0
39.
2.0
t
0
4.0
16.0
12.0
8.0
Time (s)
40.
AFIGURE 2.23 Velocity versus time See Exercises 33 and 51.
34.
Figure 2.24 shows a plot of velocity versus time for
object in linear motion. (a) Compute the acceleration
for each phase of motion. (b) Describe how the object
moves during the last time segment.
. V
41.
an
10.0
42.
8.0
6.0
4.0
2.0
t
12.0
43.
4.0
2.0
8.0
6.0
10.0
-2.0
-4.0
-6.0
-8.0
44
-10.0
-12.0
Time (s)
FIGURE 2.24 Velocity versus time See Exercises 34 and 55.
45
35. A car initially traveling to the right at a steady speed
of 25 m/s for 5.0 s applies its brakes and slows at a con-
stant rate of 5.0 m/s for 3.0 s. It then cnontinues traveling
Velocity (m/s)
Velocity (m/s)
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10.0 m (10.0, 8.0) (4.0, 8.0) 38. 8.0 f 6.0 t 4.0 39. 2.0 t 0 4.0 16.0 12.0 8.0 Time (s) 40. AFIGURE 2.23 Velocity versus time See Exercises 33 and 51. 34. Figure 2.24 shows a plot of velocity versus time for object in linear motion. (a) Compute the acceleration for each phase of motion. (b) Describe how the object moves during the last time segment. . V 41. an 10.0 42. 8.0 6.0 4.0 2.0 t 12.0 43. 4.0 2.0 8.0 6.0 10.0 -2.0 -4.0 -6.0 -8.0 44 -10.0 -12.0 Time (s) FIGURE 2.24 Velocity versus time See Exercises 34 and 55. 45 35. A car initially traveling to the right at a steady speed of 25 m/s for 5.0 s applies its brakes and slows at a con- stant rate of 5.0 m/s for 3.0 s. It then cnontinues traveling Velocity (m/s) Velocity (m/s)

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Expert Answer

Step 1

(a) The acceleration is defined as the rate of change of velocity with respect to time.

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v -u a = tz-t

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Step 2

The acceleration of object in the first segment from 1.0 s to 3.0 s.

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(8.0m/s- Om/s) (3.0s-10s 4.0m/s2

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Step 3

The acceleration of object in the seco...

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(-12.0m/s-8.0m/s) (8.0s-3.0s) = -4.0m/s |

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