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100 kg1 m

Question

The 100 kg block in figure takes 6.60 s to reach the floor after being released from rest.  What is the mass of the block on the left?

100 kg
1 m
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100 kg 1 m

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Step 1

The forces on the two masses must be equal and also the acceleration with which the two masses move must be equal.

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Step 2

The equation of motion of the ...

1
S ut at
2
Here, s is the distance moved by mass M , u is its initial velocity and t is the time taken by M to
reach the floor
The initial velocity of the 100kg mass is zero. Substitute 1 m for s, 0 m/s for u and 6.60 s for t in
the above equation
a(6.50 s
1
1 m 0 a
2m
(6.60 s)
=0.0459 m/s2
The value of g is 9.80 m/s2 .Substitute the values in equation (2).
9.80 m/s2 -0.0459 m/s2
= (100 kg)9.80 m/s2 +0.0459 m/s2
= 99.07 kg
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1 S ut at 2 Here, s is the distance moved by mass M , u is its initial velocity and t is the time taken by M to reach the floor The initial velocity of the 100kg mass is zero. Substitute 1 m for s, 0 m/s for u and 6.60 s for t in the above equation a(6.50 s 1 1 m 0 a 2m (6.60 s) =0.0459 m/s2 The value of g is 9.80 m/s2 .Substitute the values in equation (2). 9.80 m/s2 -0.0459 m/s2 = (100 kg)9.80 m/s2 +0.0459 m/s2 = 99.07 kg

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