109. Find a value of N such that /4 tan x dx < 10-4

Q: Evaluate the definite integral.

A: We have to evaluate the integration ∫0π3sec32xtanxdx

Q: 14. Find the smallest positive root of tan x+2 tanh x = 0.

A: Newton Raphson Method:- The root is xi+1 =xi - fxif'xi; i=0, 1, 2, ....   Given equation is tanx +2…

Q: Find the indefinite integral.

A: We have to solve the indefinite integral: ∫tan x3 sec2 x dx Solving the integral by substitution…

Q: Find the indefinite integral ∫sec5 x tan3 x dx

A:

Q: 5) Evaluate the integral: tan 3 x dx

A: Given integral, ∫tan3x dx

Q: In [tan (5 + )| +o sec x dx 4 2

A:

Q: 10) lim TT X-- sinx-cosx - TT X- 4

A:

Q: Evaluate the indefinite integral. 4 tan°(x) sec*(x) dx

A:

Q: Division rule

A:

Q: 3. Prove that the identity is true. sin*t- cost = tan²t-1 cos't

A:

Q: EX-15- Prove that : a) Sec-'x= Cos- ! b) Sin-' (-x)=-Sin-'x

A:

Q: Find the upper bound on the error if tan (2x')~ 2x and x< 0.2 -1

A:

Q: Find the indefinite integral ∫ 3√(tan x) sec2 x dx

A: ∫tanx3sec2x dx Now put tanx=t⇒sec2x=dtdx⇒sec2x  dx=dt

Q: Evaluate the indefinite integral: ∫sec x tan x dx

A: Given indefinite integral is ∫secxtanxdx

Q: Find integral.

A: We have to find the integral: ∫tan 7x dx We know the integration formula, ∫tan x dx=lnsec x+C∫tan ax…

Q: Find integral.

A:

Q: Find the indefinite integral ∫sec6 4x tan 4x dx

A:

Q: Write ∫ tan2k+1 x dx, where k is a positive integer, in terms of ∫ tan2k−1 x dx.

A: Given integral is ∫tan2k+1dx. Rewrite the above integral as follow.…

Q: find x in degrees Sin x=0,8766 tanx= 3.7834

A: Given that sinx=0.8766 and tanx=3.7834 To find x in degrees

Q: 2. Use reduction formula to evaluate the integral: sin xdx.

A: We have to evaluate integral by using reduction formula.

Q: 11) (y)* = (In tanx)(x*)(sin x)* %3D

A:

Q: 11) (/y)* = (In tanx)(x*)(sin x)* %3D

A:

Q: Evaluate / 5 sec2 *dx tan(x) 05 In(|tan(x)|) + C Oln(tanx) + C 05 In(x) + C 05 tan(x) + C

A:

Q: Evaluate the indefinite integral.

A: Consider the given integral I=∫sec3x·tanx dx

Q: 4. What is (Cos (x²)} dv 5. What is (tan x³) dx 6. What is (In x)7 dx

A: To find out the derivative.

Q: Expand fix)= Sin(x+ TT),O<X< I ina half range sine series

A:

Q: 7. Integrate. S tan50 sec³0d0

A:

Q: 19. Solve for x:x = (tan e + cote)² sin?e - tan?

A: Given that: x=(tanθ+cotθ)2sin2θ-tan2θ

Q: Find the indefinite integral

A:

Q: Find the indefinite integral ∫tan5 x sec4 x dx

A: Given:∫tan5(x) sec4(x)dx

Q: a. Show that y = tan u increases on every open interval in its domain. b. If the conclusion in part…

A: y=tanu Differentiating with respect to u, we get dydu=sec2u Now clearly, sec2u≥0 for every value of…

Q: 1 If f(x) = 8 tan¯¹(8 sin(2x)), f'(x) =

A: Differentiate

Q: Find the indefinite integral ∫tan5 (x/2) dx

A: It is given that, ∫tan5x2dx. We have to evaluate it.

Q: In(|tan(x) sin(x)|) = 2 In(|sin(x)]) + In(|sec(x)])

A:

Q: find maclurin formula in the fourth degree for f(x)=tanx

A:

Q: 278. Suppose that sin(ln x) = 3, and that sin(ln y) = }. If 0 < ln x < and 0 < ln y < , use the…

A:

Q: 3 tan-(x)dx = In (4) 2/3 None - In (4) 품-In (2)

A:

Q: Derive a formula for ſ tan x sec "x dx where n 40

A: Integration problem....

Q: In(tan x) -dp- sin x cos X 3 4

A: To evaluate the given definite integral.

Q: If f(x) 3 tan-'(3 sin(3x)), f'(z) =

A:

Q: Find the indefinite integral. tan“ X dx sec x

A:

Q: 3 sec x tan xdx

A: ∫π4π3secx tanx dx

Q: 7/3 In(tan x) dx T/4 sin x cos x dx

A: It is simple substitute method of integration

Q: 52. Verify that f(x) sin x is an odd function and u fact to show that '3 sin x dx < 1 -2

A:

Q: (6) Given that In= tan" x dx, show that, for n 2 2. %3D In- In-2 = %3D n- 1

A: I think given question is slightly wrong. According to me the required proof should be…

Q: 3-Еxpand In [x' sin x /Vx2 + 1]

A: According to guidelines we should have been able to solve only one question at a time #3 expand

Q: - In-2. Hence show that In = 01 tan" x dx = n - 1

A:

Q: what is the deivative oF: tan(3x) eX y = In x

A: The given function is: y=2xtan(3x)ex8ln x

Q: Lim メーvo s'in 5À sin 3X

A: Given: limx→0sin5xsin3x