11. A mutant bacterial cell has a defective aminoacyl synthase that attaches a lysine to tRNAs with the anticodon AAA instead of the normal phenylalanine. The consequence of this for the cell will be that: A. none of the proteins in the cell will contain phenylalanine B. proteins in the cell will include lysine instead of phenylalanine at amino acid positions specified by the codon UUU C. the cell will compensate for the defect by attaching phenylalanine to tRNAs with lysine-specifying anticodons D. the ribosome will skip a codon every time a UUU is encountered

11. A mutant bacterial cell has a defective aminoacyl synthase that attaches a lysine to tRNAs with the anticodon AAA instead of the normal phenylalanine. The consequence of this for the cell will be that: A. none of the proteins in the cell will contain phenylalanine B. proteins in the cell will include lysine instead of phenylalanine at amino acid positions specified by the codon UUU C. the cell will compensate for the defect by attaching phenylalanine to tRNAs with lysine-specifying anticodons D. the ribosome will skip a codon every time a UUU is encountered

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter15: From Dna To Protein

Section: Chapter Questions

Problem 4TYK

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The AUC and AUA codons in mRNA both specify isoleucine. What feature of the genetic code explains this? complementarity nonsense codons universality degeneracy
Which of the following statements is false? a. GTP is an energy source during various stages of translation. b. In the ribosome, peptidyl transferase catalyzes peptide bondformation between amino acids. c. When the mRNA code UAA reaches the ribosome, there isno tRNA to bind to it. d. A long polypeptide is cut off the tRNA in the A site so its Metamino acid links to the amino acid in the P site. e. Forty-two amino acids of a protein are encoded by 126nucleotides of the mRNA.
6a) Transcribe the following DNA sequence into codons. TACGCGACATTACATGAATCGTTTGGAGATTAGCCCTATTTCTCTAAGAACACGACTb) Excise(cut out) codons numbered 5, 6, and 7. Leave the remaining codons. c) Now translate the sequence . d) Explain how many amino acids are now in your polypeptide? e) What would happen to your polypeptide if either of your cysteine amino acids near the start or end of thepolypeptide were translated incorrectly. f) Based on your final polypeptide can you make the original DNA strand by doing reverse translation andtranscription? g) Explain if your polypeptide similar to your template strand or the complementary strand?
7. A segment of a DNA strand consists of ...GCTTAGACCTGA.... (a) Identify the expected nucleotide order in the complementary mRNA (b) Identify the sequence of amino acids coded for by this segment of DNA. (c) Describe the bond that forms during translation to link amino acids together. Identify the functional groups that react and the atoms involved.
1. Classify the type of mutation that have taken place: silent, missense and nonsense as a result of a single base substitution from UCG codon which codes for cysteine:a) AGC (ser): ________b) UGU (cys): ________c) GGC (gly): _______d) UGA (stop): _______e) UUC (phen): _______2. A single base addition and a single base deletion approximately 15 bases apart in the mRNA specifying the protein lysozyme from the bacterial virus T4 caused a change in the protein fromits wil-type composition….lys-ser-pro-ser-leu-asn-ala-ala-lys…..to the mutant form lys-val-his-his-leu-met-ala-alalys.a. Decipher the segment of mRNA for both the original protein and the double mutant.b. Which base was added? Which was deleted?3. Given is the 30 nucleotides in the human gene for hemoglobin (the oxygen-carrying protein in the red blood cells): 5’ TAC-CAC-GTG-GAC-TGA-GGA-CTC-CTC-TTC-AGA 3’a. What is the complementary strand?b. Deduce the mRNA in this coding region.c. What is the amino acid sequence based on this…
6. Please describe the events that may result in a mature protein not having methionine asthe N-terminal amino acid.
1. Considering the following nucleotide sequence in an mRNA molecule: 5’ AUG UUA CGU AAU GCU GUC GAA UCU AUU UGC UUU ACA UAA 3' a) Write the sequence of the DNA template (antisense) strand from which the mRNA was synthesized. b) Write the sequence of the DNA coding (sense or informational) strand complementary to the template strand. c) Write the sequence of tRNA anticodon that corresponds to the given mRNA molecule. d) Write the amino acid sequence of the peptide synthesized from the given mRNA nucleotide sequence. e) Draw the structure of the pertide fragment made up of the first five (5) amino acids in the given polypeptide.
1. A region of DNA in a particular cell synthesizes a segment of RNA that is 174 bases long and in the form of a large palindrome. The RNA is transported to the cytoplasm and folds into a hairpin loop of double stranded RNA. In the cytoplasm, the hairpin loop is recognized by a double-stranded RNA cutting enzyme (dicer) and is cut into 21 BP lengths. When these 21 BP double stranded segments are combined with protein, they function by: Answer choices destroying specific mRNAs priming the synthesis of DNA sequences adding DNA to the chromosome ends (telomeres) acting as decoys for RNA degrading enzymes thus protecting the mRNAs present splicing the introns out of messenger RNA 2. The following are genotypes of merozygotes of E. coli with various combinations of lac operon mutations. Determine the phenotype with respect to beta-galactosidase (z), permease (y), and trans-acetylase (a) of each combination as U = uninducible, I = inducible, and C = constitutive. Choose from…
1. Considering the following nucleotide sequence in an mRNA molecule: 5’ AUG UUA CGU AAU GCU GUC GAA UCU AUU UGC UUU ACA UAA 3' d) Write the amino acid sequence of the peptide synthesized from the given mRNA nucleotide sequence. e) Draw the structure of the pertide fragment made up of the first five (5) amino acids in the given polypeptide.
1. A tRNA to which the correct amino acid has been attached is called?
5) The peptidyltransferase reaction begins with the hydrolysis or breaking of the bond between the carboxyl group of the last amino acid added to the growing polypeptide and the 3' end of the tRNA in the P site. How does the ribosome get the necessary activation energy to catalyze that hydrolysis reaction?
3. In studying normal and mutant forms of a particularhuman enzyme, a geneticist came across a particularly interesting mutant form of the enzyme. Thenormal enzyme is 227 amino acids long, but themutant form was 312 amino acids long. The extra85 amino acids occurred as a block in the middleof the normal sequence. The inserted amino acidsdo not correspond in any way to the normal proteinsequence. What are possible explanations forthis phenomenon? How would you distinguishamong them?