Question

Asked Oct 10, 2019

6 views

Find the probability of each

Step 1

**11.a. The probability of it was a cheese pizza eaten at work is obtained below:**

From the given information, number of cheese pizzas is 24, one or more topping pizzas is 16. The 12 cheese pizzas were eaten at work and 10 one or more topping pizzas were eaten at work.

Total number of pizzas=24+16=40.

The required probability is,

Step 2

**11.b. The probability of it was pizza with either or more toppings and it was not eaten at work is obtained below:**

Let *A* be the event that pizza with either one or more toppings, *B* be the event that pizzas were not eaten at work.

The number of pizzas not eaten at work=40-(10+12)=18

The required probability is,

Step 3

**11.c. The probability of it was cheese pizza, or it was a pizza eaten at work is obtained below:**

Let *A* be the event that cheese pizza, *B* be the event that pizzas were eaten at work.

The number of pizzas eate...

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