11. Suppose that a department contains 15 men and 10 women. How many ways are there to form a committee with five members if it must have more women than men? а) С (25,5) — С(10,5) b) С (15,3) С(10,2) + С(15,4) . С(10,1) + C(15,5) : С(10,0) с) С (15,4) . С(10,2) + C(15,5) - С(10,1) + C(15,6) : С(10,0) d) C(10,3) · C(15,2) + C(10,4) · C(15,1) + C(10,5) · C(15,0) e) C(25,5) – C(15,5)
Permutations and Combinations
If there are 5 dishes, they can be relished in any order at a time. In permutation, it should be in a particular order. In combination, the order does not matter. Take 3 letters a, b, and c. The possible ways of pairing any two letters are ab, bc, ac, ba, cb and ca. It is in a particular order. So, this can be called the permutation of a, b, and c. But if the order does not matter then ab is the same as ba. Similarly, bc is the same as cb and ac is the same as ca. Here the list has ab, bc, and ac alone. This can be called the combination of a, b, and c.
Counting Theory
The fundamental counting principle is a rule that is used to count the total number of possible outcomes in a given situation.
subject:discrete structures
there may be several correct answers
Suppose that a department contains 15 men and 10 women. How many ways are there to form a committee with five members if it must have more women than men?
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
