Question

Can you help me step by step with this problem?

Step 1

Let the given function is y=4/(3x+12).

The graph of y has vertical asymptotes at those values of x at which the denominator is equal to zero.

Hence the given function has vertical asymptotes at:

Step 2

Thus, the graph will have vertical asymptotes at x = - 4 line.

Step 3

To find the horizontal asymptote, if the degree of denominator is greater than the degree of numerator then the graph of the function will have a horizontal asym...

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Sorry about that. What wasn’t helpful?