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- 1. Given that x=5 and y=- 10, what is the output of this code If (x>10 && y<x-5) { If (x || y) x = 9; } else y =10; printf(“%d %d”, y,x); ? (Explain) Answer: write C ReplCan someone please explain this code, although the code is correct, can you explain how it works detailed. Input: nums = [2,7,11,15], target = 9 Output: [0,1] Output: Because nums[0] + nums[1] == 9, we return [0, 1].6. Write a program to display the multiplication table vertically from 1 to n. Your output may resemble the following:Display the multiplication table vertically from 1 to n:-------------------------------------------------------------Input the number of the multiplication table: 5Multiplication table from 1 to 51x1= 1 2x1= 2 3x1= 3 4x1= 4 5x1= 51x2= 2 2x2= 4 3x2= 6 4x2= 8 5x2= 101x3= 3 2x3= 6 3x3= 9 4x3= 12 5x3= 151x4= 4 2x4= 8 3x4= 12 4x4= 16 5x4= 201x5= 5 2x5= 10 3x5= 15 4x5= 20 5x5= 251x6= 6 2x6= 12 3x6= 18 4x6= 24 5x6= 301x7= 7 2x7= 14 3x7= 21 4x7= 28 5x7= 351x8= 8 2x8= 16 3x8= 24 4x8= 32 5x8= 401x9= 9 2x9= 18 3x9= 27 4x9= 36 5x9= 451x10= 10 2x10= 20 3x10= 30.
- 6. A) write the following expression in C++. B) Write equivalent expressions for each of the following by using De Morgan’s Law !(x < 5) !(x < 5) && !(y >= 7) !(a == b)Explain output for line 10 to 16i want to run this code Instead of letters, I want numbers, how? please help # multiples.s -- takes two numbers A and B, and prints out # all the multiples of A from A to A * B. # If B <= 0, then no multiples are printed. # Registers used: # $t0 - used to hold A. # $t1 - used to hold B. # $t2 - used to store S, the sentinel value A * B. # $t3 - used to store m, the current multiple of A. .text main: li $v0, 5 # syscall 5 = read_int syscall move $t0, $v0 # A = integer just read li $v0, 5 # syscall 5 = read_int syscall move $t1, $v0 # B = integer just read blez $t1, exit # if B <= 0, exit. mul $t2, $t0, $t1 # S = A * B. move $t3, $t0 # m = A loop: move $a0, $t3 # print m. li $v0,1 # syscall 1 = print_int syscall # make the system call. beq $t2, $t3, endloop # if m == S, we're done. add $t3, $t3, $t0 # otherwise, m = m + A.
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