The first question 12–89. The girl at A can throw a ball at va = 10 m/s.Calculate the maximum possible range R = Rmax and theassociated angle 0 at which it should be thrown. Assume theball is caught at B at the same elevation from which it is%3Dthrown.12–90. Show that the girl at A can throw the ball to theboy at B by launching it at equal angles measured up ordown from a 45° inclination. If va = 10 m/s, determinethe range R if this value is 15°, i.e., 0, = 45° – 15° = 30°and 62 = 45° + 15° = 60°. Assume the ball is caught at thesame elevation from which it is thrown.VA = 10 m/sB]R

Given vA=10m/sAskedRmax=?θ=?SolutionFor the given condition we have v2=u2+gRmaxHere u=0and for Rmax…

12–89. The girl at A can throw a ball at va = 10 m/s. Calculate the maximum possible range R = Rmax and the associated angle 0 at which it should be thrown. Assume the ball is caught at B at the same elevation from which it is thrown.

12–89. The girl at A can throw a ball at va = 10 m/s. Calculate the maximum possible range R = Rmax and the associated angle 0 at which it should be thrown. Assume the ball is caught at B at the same elevation from which it is thrown.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

The first question

12–89. The girl at A can throw a ball at va = 10 m/s.
Calculate the maximum possible range R = Rmax and the
associated angle 0 at which it should be thrown. Assume the
ball is caught at B at the same elevation from which it is
%3D
thrown.
12–90. Show that the girl at A can throw the ball to the
boy at B by launching it at equal angles measured up or
down from a 45° inclination. If va = 10 m/s, determine
the range R if this value is 15°, i.e., 0, = 45° – 15° = 30°
and 62 = 45° + 15° = 60°. Assume the ball is caught at the
same elevation from which it is thrown.
VA = 10 m/s
B]
R

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