Question
Asked Jul 1, 2019

Hello, 

I am having trouble in finding the difference between these equations to find the solutions. 2pi vs. pi/2

12sin'-9-0
Jcos-1
COS=
cose
sinewhy can it not
COSE=
Solution
Set
3
t S
4T
3
=51 +k
Solution
Set
.t
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12sin'-9-0 Jcos-1 COS= cose sinewhy can it not COSE= Solution Set 3 t S 4T 3 =51 +k Solution Set .t

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Expert Answer

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Step 1

Consider the provided trigonometry equation.

12sin 0-9 0
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12sin 0-9 0

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Step 2

Now the above equation can be written as:

12sin2 9
9
V12
sin 0
or sin 0
2
2
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12sin2 9 9 V12 sin 0 or sin 0 2 2

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Step 3

As we know in first and second quadrant the value of sin (θ) is ...

for sin e
2
2T
2Tk (2nd Quadrant)
3
+2Tk (1st Quadrant) or
3
for sin
2
47T
+2Tk (3rd Quadrant)
27Tk (4th Quadrant)
or
3
3
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for sin e 2 2T 2Tk (2nd Quadrant) 3 +2Tk (1st Quadrant) or 3 for sin 2 47T +2Tk (3rd Quadrant) 27Tk (4th Quadrant) or 3 3

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Calculus

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