Question
Asked Nov 13, 2019
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13.47 A sulfuric acid solution containing 571.6 g of H2SO4 per
liter of solution has a density of 1.329 g/cm2. Calculate
(a) the mass percentage, (b) the mole fraction, (c) the mo-
lality, (d) the molarity of H2SO4 in this solution.
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13.47 A sulfuric acid solution containing 571.6 g of H2SO4 per liter of solution has a density of 1.329 g/cm2. Calculate (a) the mass percentage, (b) the mole fraction, (c) the mo- lality, (d) the molarity of H2SO4 in this solution.

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Expert Answer

Step 1

(a)The mass percentage of sulfuric acid solution can be calculated as

Given, weight of H,SO=571.6g
density-1.329g/cm3
1000mL contains1329 g of H,SO
weight of H SO
-x100
Mass percentage=.
molarmassof compound
571.6gx100%
1329g
43%
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Given, weight of H,SO=571.6g density-1.329g/cm3 1000mL contains1329 g of H,SO weight of H SO -x100 Mass percentage=. molarmassof compound 571.6gx100% 1329g 43%

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Step 2

(b) The mole fraction of sulfuric acid solution can be calculated as

mass
moles of HSO
molar mass
571.6g
98g/mol
--5.83 mol
1329-571.6
moles of H20
=42.07 mol
18
moles of solute
Mole fraction
Totalmoles of solution
5.83mol
5.83mol+42.07 mol
0.121
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mass moles of HSO molar mass 571.6g 98g/mol --5.83 mol 1329-571.6 moles of H20 =42.07 mol 18 moles of solute Mole fraction Totalmoles of solution 5.83mol 5.83mol+42.07 mol 0.121

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Step 3

(c) The molality of sulfuric acid s...

Massof solvent-1329-571.6g=757.4g
757.4g-0.7574kg
weight
1
Molality
mole cular weight
weight of solvent inkg
571.6g
98g/molx0.7574 kg
7.70 molkg
=7.70 m
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Massof solvent-1329-571.6g=757.4g 757.4g-0.7574kg weight 1 Molality mole cular weight weight of solvent inkg 571.6g 98g/molx0.7574 kg 7.70 molkg =7.70 m

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