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PhysicsQ&A Library(13%) Problem 5: A rock takes 2.05 s to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.2 m/s.50% Part (a) Calculate the height of the cliff in m.h =7 8 9sin()cos()tan()НOMEE 1^A 4 5 61 2 3asin()acos()cotan()atan()sinh()acotan()cosh()tanh()cotanh()ENDRadiansDegreesVO BACKSPACECLEARDELI give up!SubmitFeedbackHintHints: 1 for a 0% deduction. Hints remaining: 0Feedback: 2 for a 0% deduction|-Choose a system of coordinates before attempting any calculation. Keep in No meaningful feedback available for the current submission.mind that the initial velocity and acceleration have opposite signs, and thatthe height of an object can only be positive.50% Part (b) How long would it take to reach the ground if it is thrown straight down with the same speed?Question

Asked Feb 2, 2020

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Need help with parts a and b im lost on how to do them

Step 1

**Given**

Initial velocity u = 8.2 m/s

Duration t = 2.05 s

Step 2

**Solution **

Part A

When thrown straight up the acceleration and the initial velocity are in opposite direction

Step 3

Part B

When thrown straight down, the acceleration is and th...

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