Question
Asked Nov 11, 2019
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14. A 980-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are
locked, and the two cars skid forward 2.6 m before stopping. The police officer, estimating the coefficient of kinetic friction
between tires and road to be 0.80, calculates the speed of the sports car at impact. What was that speed?
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14. A 980-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.6 m before stopping. The police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact. What was that speed?

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Expert Answer

Step 1

Given values:

 M1 = 980 kg

M2 = 2300 kg

Coefficient of kinetic friction = 0.80

Let the speed of the sport car be V1.

Speed of the SUV, V2 = 0 m/s

Step 2

The deacceleration in the cars can be calculated by the formula of frictional force:

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(M, + M2-a)4(M + M2)g a -g a=-0.80 x9.8 =-7.84 m/s2

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Step 3

The common velocity of the cars before stopping can be ...

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2u2as 02 2-2x 7.84 x 2.6 u = 40.768 =6.38 m/s

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