140 students at a college were asked whether they had completed their required English 101 course, and 73 students said "yes". Construct the 80% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p <

Q: Express the confidence interval 30.8 % ± 7.3 % in the form of a trilinear inequality. % < p<

A: Given, The objective is express the confidence interval 30.8% ± 7.3% in the form of trilinear…

Q: Let T represent the percentage of all female students who would receive a grade of A on this test.…

A: Given : Sample Size, n = 47 Number of successes, x = 14 confidence level,c=0.99

Q: s the confidence interval 41.4%±3.8%41.4%±3.8% in the form of a trilinear inequality?

A: The confidence interval in the trilinear form can be written as: Lower limit &lt; p &lt; Upper limit…

Q: Express the confidence interval 481.5 ± 118.1 in the form of a trilinear inequality. < µ <

A:

Q: 2. A nutritionist wants to know the population proportion of Grade 1 learners who eat vegetables.…

A: We have given thatn = 1200x = 200p̂ = x/n = 200/1200 = 0.167Significance level (α) = 1 - 0.95 = 0.05

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.9% confidence…

A: Sample proportion: Z-critical value: given: Refer Standard normal table/Z-table OR use excel…

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

A:

Q: Let represent the percentage of all students who received a grade of B given they were male. Use a…

A:

Q: Express the confidence interval 85.9%±5.8%85.9%±5.8%in the form of a trilinear inequality. %…

A: Given confidence interval is,

Q: According to a Gallup Poll taken in East Germany, when adults were asked whether they were thriving,…

A:

Q: Express the confidence interval 766.5 + 56.6 in the form of a trilinear inequality. <μ<

A: Given that  766.5 ± 56.6 Where  Point estimate =766.5  Margin of error =E=56.6

Q: A psychologist is interested in constructing a 99% confidence interval for the proportion of people…

A: Solution: Given information: n= 746 Sample size  x = 56 Successes  p^=xn=56746= 0.0751    Sample…

Q: xpress the confidence interval 243.2±133.9243.2±133.9 in the form of a trilinear inequality. <μ

A: The confidence interval is given in the form of, Point estimate ± Margin of error = Sample mean ±…

Q: Construct a 90% confidence interval, using the inequality d-te <d+tc To test the effectiveness of a…

A: The difference is, Sleep without the drug Sleep using the drug Difference(d) 4.4 5.5 -1.1 4.1…

Q: A psychologist is interested in constructing a 99% confidence interval for the proportion of people…

A:

Q: Express the confidence interval 71.9 % ± 4.7 % in the form of a trilinear inequality. % <p < %…

A: Hence,

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

A: Since the question requires accurate results, I will use excel to solve this question.…

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

A: HERE n= 150 p^ = 0.56

Q: Express the confidence interval 28.9%±4.7% in the form of a trilinear inequality.

A: From the provided information, The confidence interval is in the form: 28.9% ± 4.7%

Q: A psychologist is interested in constructing a 99% confidence interval for the proportion of people…

A: Given that,x=62,n=813 (a) The sample proportion is, Critical values: By using the standard normal…

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.9% confidence…

A: Solution: Let X be the number of successes and n be the sample size. From the given information,…

Q: Express the confidence interval 35.5 % +7% in the form of a trilinear inequality. * <p<

A:

Q: Express the confidence interval 81.6 % + 6.4 % in the form of an inequality. Fill in blanks with…

A: The given confidence interval is 81.6% ± 6.4%

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.9% confidence…

A: Given,  x = 30 n = 114

Q: Express the confidence interval 769.4±123.6769.4±123.6 in the form of a trilinear inequality.…

A:

Q: Express the confidence interval 88.9 % ± 4.9 % in the form of a trilinear inequality. % <p < %

A: The confidence interval is calculated as,CI = Point estimate ± Margin of errorSubstitute the given…

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

A:

Q: Express the confidence interval 46.1 % 5.1% in the form of a trilinear inequality. % <p< Submit…

A: It is given that the confidence interval  46.1% ± 5.1%

Q: Express the confidence interval 15.1 % ± 6.5% in the form of an inequality. Fill in blanks with…

A:

Q: Express the confidence interval 41.6%±6.2%41.6%±6.2% in the form of a trilinear inequality using…

A: Given:  confidence interval 41.6%±6.2%

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.9% confidence…

A: The sample proportion of the sample of size n can be defined as: p^=xn Here, x = Total number of…

Q: A psychologist is interested in constructing a 99% confidence interval for the proportion of people…

A: Solution-:  Given: n=705,X=56,α=0.01 We want to find, (a) With 99% confidence the proportion of all…

Q: (a) Find a point estimate for the true proportion of all workers that would have hearing impairment.…

A: 8. A study was conducted on hearing impairment among workers in a construction site.

Q: Express the confidence interval 51.3%±4.2%51.3%±4.2% in the form of a trilinear inequality.

A: Solution: Here, the confidence interval for the percentage would be calculated. Then, the confidence…

Q: Express the confidence interval 63.4 % + 3.6 % in the form of a trilinear inequality. 6 <p <

A: Solution: 11. From the given information, the confidence interval for the population proportion is…

Q: Express the confidence interval 830.9 ± 133.7 in the form of a trilinear inequality. < µ <

A: To express the Confidence Interval 830.9±133.7 in the form of tri linear inequality: For lower…

Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…

A:

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a…

A: Given Information:  In a survey of 3674 adults in a​ country, 48​% believe the economy is getting…

Q: Express the confidence interval 19.8 % ± 4.2 % in the form of a trilinear inequality. % <p<

A: Given, CI = 19.8%±4.2%

Q: Express the confidence interval 704.1±141.1704.1±141.1 in the form of a trilinear inequality.…

A: We have to express the given confidence interval in the form of trilinear inequality. 704.1±141.1 We…

Q: A recent study of 750 internet users in Europe found that 35% of internet users were women. What is…

A: It is given that the study of 750 internet users in Europe found that 35% of internet users were…

Q: 99 students at a college were asked whether they had completed their required English 101 course,…

A: Here, α = 0.20 (= 1 – 80%). Using Excel formula “=NORM.S.INV(1-(0.20/2))”, the critical value at 80%…

Q: Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval…

A: From the given information, let X be the number of successes.  X = 74. Let n be the total number of…

Q: Find the 99% confidence interval. Enter your answer as a tri-linear inequality accurate to two…

A: We have been given a sample of 53 to find the confidence interval for the population mean.

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.9% confidence…

A: Given: The size of the sample is n=118. The proportion of success is p^=0.30. The level of…

Q: Express the confidence interval 76.1 % + 7.9 % in the form of a trilinear inequality. % <p<

A: Solution Step 1 Given confidence interval is 76.1 % +/- 7.9% So ( 76.1℅ -7.9 %  , 76.1% + 7.9%) (…

Q: A TV report conducted a survey of 908 people in Phoenix metro area and found that 28% of the…

A: Given Total people n = 908 Probability p = 0.28 we are 94% confident that the true proportion of…

Q: Express the confidence interval 31.9 % ± 4.7 % in the form of a trilinear inequality. % <р<

A: Given that  31.9 % ±  4.7%

Q: Express the confidence interval 53.8 % + 5.2 % in the form of a trilinear inequality. % <p<

A: lower limit=&gt; 53.8-5.2% Upper limit=&gt; 53.8+5.2%

Q: A random sample of 340 college students were asked if they believed that places could be haunted,…

A: