15.The eakth (6x10 kg) revolves around the sun with angular velocity of 2x10" rad/sec in a circular orbit ofradius 10 kenihe force exerted by the sun on the earth is:b) zero Nc) 27x10" Nd) 36x10" N

Given, mass of earth = 6 x 1024 Kg Angular velocity ω=2×10-7 rad/sec Radius of circular orbit r =1.5…

15.Theenhh (6xI0 kg) revolves around the sun with angular velocity of 2x10" rad/sec in a circular orbit of radius ásto k he force exerted by the sun on the earth is: b) zero N c) 27x10" N d) 36x10" N

15.Theenhh (6xI0 kg) revolves around the sun with angular velocity of 2x10" rad/sec in a circular orbit of radius ásto k he force exerted by the sun on the earth is: b) zero N c) 27x10" N d) 36x10" N

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter10: Fixed-axis Rotation

Section: Chapter Questions

Problem 108AP: Calculate the angular velocity of the orbital motion of Earth around the Sun.

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Concept explainers

Angular speed, acceleration and displacement

Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.

Angular Position

Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.

Question

15.The eakth (6x10 kg) revolves around the sun with angular velocity of 2x10" rad/sec in a circular orbit of
radius 10 kenihe force exerted by the sun on the earth is:
b) zero N
c) 27x10" N
d) 36x10" N

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