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*16. Ron pulls with a string on a wooden blo ck of mass m = 80 kg. The tensionin the string is 300 N and the string makes anhorizontal, as shown. The floor is very rough (H = 0.35 and ug = 0.75) and theblock does not moveStringangle of 37° with respect to the37a) Draw a free-body diagram for the blockb) Find the magnitude of the normal force exerted by the floor on the blockc) Find the magnitude of the frictional force exerted by the floor on the block.

Question
*16. Ron pulls with a string on a wooden blo ck of mass m = 80 kg. The tension
in the string is 300 N and the string makes an
horizontal, as shown. The floor is very rough (H = 0.35 and ug = 0.75) and the
block does not move
String
angle of 37° with respect to the
37
a) Draw a free-body diagram for the block
b) Find the magnitude of the normal force exerted by the floor on the block
c) Find the magnitude of the frictional force exerted by the floor on the block.
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*16. Ron pulls with a string on a wooden blo ck of mass m = 80 kg. The tension in the string is 300 N and the string makes an horizontal, as shown. The floor is very rough (H = 0.35 and ug = 0.75) and the block does not move String angle of 37° with respect to the 37 a) Draw a free-body diagram for the block b) Find the magnitude of the normal force exerted by the floor on the block c) Find the magnitude of the frictional force exerted by the floor on the block.

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Step 1

(a)

Consider the FBD of the block as shown.

Т
Tsin37
370
Tcos370
f
mg
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Т Tsin37 370 Tcos370 f mg

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Step 2

Here, N is the normal reaction force that acts on the block and f is the friction’s force.

(b)

Since the block is at rest, the net horizontal and vertical forces that act on the block must be zero each.

Equate the net vertical forces to zero. Take the forces along the upward direction to be positive.

Tsin 370 N- mg = 0
N mg -T sin370
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Tsin 370 N- mg = 0 N mg -T sin370

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Step 3

Substitute 300 N for T and 80 ...

N (80 kg) (9.8 m/s2)-(300 N)sin 37°
1 N
= 784 kg m s
-180.54 N
-2
1 kg m s
-603.46 N
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N (80 kg) (9.8 m/s2)-(300 N)sin 37° 1 N = 784 kg m s -180.54 N -2 1 kg m s -603.46 N

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Science

Physics

Newtons Laws of Motion

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