17(8)up TupUse this result in Eq. 4 to produce the second term in the Taylor series expansion for f(b) about f(a)dnup TupRepeat this entire procedure to extend the representation for f(b) to obtain the third term in the Taylorseries expansion and thus illustrate how one obtains a representation for f(b) that involves only thefunction and its derivatives evaluated at x=a . Keep in mind that the only mathematical tools used in thisderivation are the definition of the definite integral and the rule for differentiating a product'.5-32. A gas mixture leaves a solvent recovery unit as illustrated in Figure 5.32. The partial pressure ofbenzene in this stream is 80 mm Hg and the total pressure is 750 mm Hg. The volumetric analysis of thegas, on a benzene-free basis, is 15% CO,, 4% O, and the remainder is nitrogen. This gas is compressed2to 5 atm and cooled to 100 F. Calculate the percentage of benzene condensed in the process. Assume thatCO2, 02 and N2 are insolub le in benzene, thus the liquid phase is pure benzene.9. Stein, S.K. and Barcellos, A. 1992, Calculus and Analytic Geometry, Chapters 3 and 5, McGraw-Hill, Inc., NewYork. compressor andheat exchanger160Chapter 5gas in equilibrium withliquid benzene at 100 Fcrwovig>4solvent recoveryunitcondensedbenzeneFigure 5.32. Recovery-condenser systemby Eq. 11 in Example 5.8.

Question
Asked Nov 11, 2019
14 views
17
(8)
up Tup
Use this result in Eq. 4 to produce the second term in the Taylor series expansion for f(b) about f(a)
dn
up Tup
Repeat this entire procedure to extend the representation for f(b) to obtain the third term in the Taylor
series expansion and thus illustrate how one obtains a representation for f(b) that involves only the
function and its derivatives evaluated at x=a . Keep in mind that the only mathematical tools used in this
derivation are the definition of the definite integral and the rule for differentiating a product'.
5-32. A gas mixture leaves a solvent recovery unit as illustrated in Figure 5.32. The partial pressure of
benzene in this stream is 80 mm Hg and the total pressure is 750 mm Hg. The volumetric analysis of the
gas, on a benzene-free basis, is 15% CO,, 4% O, and the remainder is nitrogen. This gas is compressed
2
to 5 atm and cooled to 100 F. Calculate the percentage of benzene condensed in the process. Assume that
CO2, 02 and N2 are insolub le in benzene, thus the liquid phase is pure benzene.
9. Stein, S.K. and Barcellos, A. 1992, Calculus and Analytic Geometry, Chapters 3 and 5, McGraw-Hill, Inc., New
York.
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17 (8) up Tup Use this result in Eq. 4 to produce the second term in the Taylor series expansion for f(b) about f(a) dn up Tup Repeat this entire procedure to extend the representation for f(b) to obtain the third term in the Taylor series expansion and thus illustrate how one obtains a representation for f(b) that involves only the function and its derivatives evaluated at x=a . Keep in mind that the only mathematical tools used in this derivation are the definition of the definite integral and the rule for differentiating a product'. 5-32. A gas mixture leaves a solvent recovery unit as illustrated in Figure 5.32. The partial pressure of benzene in this stream is 80 mm Hg and the total pressure is 750 mm Hg. The volumetric analysis of the gas, on a benzene-free basis, is 15% CO,, 4% O, and the remainder is nitrogen. This gas is compressed 2 to 5 atm and cooled to 100 F. Calculate the percentage of benzene condensed in the process. Assume that CO2, 02 and N2 are insolub le in benzene, thus the liquid phase is pure benzene. 9. Stein, S.K. and Barcellos, A. 1992, Calculus and Analytic Geometry, Chapters 3 and 5, McGraw-Hill, Inc., New York.

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compressor and
heat exchanger
160
Chapter 5
gas in equilibrium with
liquid benzene at 100 F
cr
wovig
>4
solvent recovery
unit
condensed
benzene
Figure 5.32. Recovery-condenser system
by Eq. 11 in Example 5.8.
help_outline

Image Transcriptionclose

compressor and heat exchanger 160 Chapter 5 gas in equilibrium with liquid benzene at 100 F cr wovig >4 solvent recovery unit condensed benzene Figure 5.32. Recovery-condenser system by Eq. 11 in Example 5.8.

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Expert Answer

Step 1

Vapor pressure of benzene in gas mixture before compression is given as 80 mmHg.

Total pressure of the gas mixture before compression is given as 750 mmHg.

Mole fraction of benzene in the gas mixture before compression on benzene-free basis will be:

Partial preassure of Benzene
Partial pressure of benzene-free gas
(x3 )
initial
80 mmHg
(750-80) mmHg
=0.12
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Partial preassure of Benzene Partial pressure of benzene-free gas (x3 ) initial 80 mmHg (750-80) mmHg =0.12

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Step 2

This can also be written as:

Moles of benzene
(x3)mitaMoles of benzene-free gas
Moles of benzene
0.12=
Moles of benzene-free gas
Moles of benzene 0.12 x (Moles of benzene-free gas)
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Moles of benzene (x3)mitaMoles of benzene-free gas Moles of benzene 0.12= Moles of benzene-free gas Moles of benzene 0.12 x (Moles of benzene-free gas)

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Step 3

When this gas is cooled and compressed  to 100  ̊F and 5 atm (3800 mmHg) , liquid...

100 32
C
100 F =
1.8
=37.78 C
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100 32 C 100 F = 1.8 =37.78 C

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