These (:
17. -3 х2+x-12 4х+16 2х-4 18. 4х2 х+1 8х-16 6х 8х-16 19. Зx+3 5х-10 5х 20. х+4 20 2 21. х-4 1 2х+2 х+4 5х-20
We’ll answer the first question since the exact one wasn’t specified. Please submit a new question specifying the one you’d like answered.
We have to factor the expressions.
For x^2+x-12. We factor -12 so that sum of the factors = 1
-12= (4)(-3)
And 4+(-3)=1
So we write x as 4x-3x
For 4x+16 used GCF method. GCF of 4 and 16 is 4. So factored out 4.
х-3 4х+16 х?+x-12 х+1 х-3 4(х+4) х?+4х-3х-12 х+1
Then factor by grouping for x^2...
х-3 4(х+4) х?+4x-3х-12 X+1 х-3 4(х+4) x(x+4)-3(x+4) 4(х+4) х+1 х-3 (х+4)(х-3) x+1
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