Question

Step 1

**Frequency distribution:**

The number of values lying in the particular interval or the number of times each value repeats is the frequency of that particular class interval or event. The frequencies are calculated by using the tally mark.

Step 2

**Obtain the frequency distribution for the dataset of maximum wind speeds:**

The dataset of maximum wind speeds is arranged in ascending order as follows:

48, 53, 53, 59, 59, 62, 63, 64, 64, 64, 67, 67, 67, 68, 69, 70, 70, 70, 71, 72, 72, 72, 72, 74, 75, 75, 75, 76, 76, 76, 77, 77, 77, 78, 78, 83, 85, 87, 92, 93.

The minimum and maximum values of the dataset of maximum wind speeds are 48 and 93.

Here, number of values of maximum wind speed falls under the specified interval is the frequency of that particular class interval of maximum wind speeds.

*Procedure for constructing the frequency distribution:*

Step by step procedure for constructing the frequency distribution is given below:

- The first lower bound should be the minimum value or a number smaller than the minimum value of the variable “maximum wind speeds”. That is, the first lower bound should be 48.
- The number of values of maximum wind speed falls under the specified interval is the frequency of that particular class interval of maximum wind speeds.
- The number of class intervals must be 7.
- Find the class width as (maximum value – minimum value)/ number of classes.
- Add the ...

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