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Asked Sep 13, 2019
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A small 12.7 g plastic ball is tied to a very light 28.7 cm string that is attached to the vertical wall of a room. A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.30 μC , you observe that it remains suspended, with the string making an angle of 17.4 ∘ with the wall.

a) Find the magnitude of the electric field in the room.

b) Find the direction of the electric field in the room: to the left or to the right

 

 

17.40
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17.40

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Step 1
Step 2

Given information:

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gauor Safomatin Mess of Plosdie all m)> 2 39 12.XL0 dength of dhe tring (A): 28.7om 28. xom hooy ra the rall (9) = -1-30 AC with woll (e) 17.40

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Step 3

Drawing free body diagram of th...

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Ale Jall Tsim& whure Eq due fpeom FBDaf ball FBD of Jall Pltrie ofeikd ue con u he Tcos =mg Tsime: Eq from y0 12-3X1O.8 m/s T m Cose Cosi7.40 T:0 13N

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