19. k(0.050 m) – (0.15)(0.12 kg)(9.8 m/s²) = (0.12 kg)(0.65 m/s²)

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I need help with number 19 please

Exercises 18-19: You are given the equation that is used to solve a problem. For each of these:
a. Write a realistic physics problem for which this is the correct equation. Look at worked ex-
amples and end-of-chapter problems in the textbook to see what realistic physics problems
are like. Be sure that the problem you write, and the answer you ask for, is consistent with
the information given in the equation.
b. Draw a free-body diagram or force diagram for your problem.
c. Finish the solution of the problem.
18. n + T -- 80 N = 0
(0.60 m) T – (0.50 m)(80 N) = 0
19. k(0.050 m) -- (0.15)(0.12 kg)(9.8 m/s²) = (0.12 kg)(0.65 m/s²)
Transcribed Image Text:Exercises 18-19: You are given the equation that is used to solve a problem. For each of these: a. Write a realistic physics problem for which this is the correct equation. Look at worked ex- amples and end-of-chapter problems in the textbook to see what realistic physics problems are like. Be sure that the problem you write, and the answer you ask for, is consistent with the information given in the equation. b. Draw a free-body diagram or force diagram for your problem. c. Finish the solution of the problem. 18. n + T -- 80 N = 0 (0.60 m) T – (0.50 m)(80 N) = 0 19. k(0.050 m) -- (0.15)(0.12 kg)(9.8 m/s²) = (0.12 kg)(0.65 m/s²)
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