199935200286.8200129200489.8200322200690.7200523200897.42007202010106.52009202012111.4Svloe 12 1atSource: Centers for111.52014Disease Control andSource: www.tvbythenumbers.comPrevention.For the points P and Q, find (a) the distance d(P, Q) and (b) the coordinates of the mid-point M of line segment PQ. See Examples 2 and 5(a).15. P(-5,-6), Q(7, -1)16. P(-4, 3), Q(2,-5)17. P(8, 2), Q(3, 5)18. P(-8, 4), Q(3, -5)20. P(6, -2), Q(4, 6)19. P(-6, -5), Q(6, 10)P-Vi.8V3), o(si.-V3)P(3V2, 4V5), (V2, -V5)22.21.

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Asked Sep 22, 2019
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Question 15, please.

1999
35
2002
86.8
2001
29
2004
89.8
2003
22
2006
90.7
2005
23
2008
97.4
2007
20
2010
106.5
2009
20
2012
111.4
Svloe 12 1at
Source: Centers for
111.5
2014
Disease Control and
Source: www.tvbythenumbers.com
Prevention.
For the points P and Q, find (a) the distance d(P, Q) and (b) the coordinates of the mid-
point M of line segment PQ. See Examples 2 and 5(a).
15. P(-5,-6), Q(7, -1)
16. P(-4, 3), Q(2,-5)
17. P(8, 2), Q(3, 5)
18. P(-8, 4), Q(3, -5)
20. P(6, -2), Q(4, 6)
19. P(-6, -5), Q(6, 10)
P-Vi.8V3), o(si.-V3)
P(3V2, 4V5), (V2, -V5)
22.
21.
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1999 35 2002 86.8 2001 29 2004 89.8 2003 22 2006 90.7 2005 23 2008 97.4 2007 20 2010 106.5 2009 20 2012 111.4 Svloe 12 1at Source: Centers for 111.5 2014 Disease Control and Source: www.tvbythenumbers.com Prevention. For the points P and Q, find (a) the distance d(P, Q) and (b) the coordinates of the mid- point M of line segment PQ. See Examples 2 and 5(a). 15. P(-5,-6), Q(7, -1) 16. P(-4, 3), Q(2,-5) 17. P(8, 2), Q(3, 5) 18. P(-8, 4), Q(3, -5) 20. P(6, -2), Q(4, 6) 19. P(-6, -5), Q(6, 10) P-Vi.8V3), o(si.-V3) P(3V2, 4V5), (V2, -V5) 22. 21.

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Expert Answer

Step 1

a)

The given points are P (–5, –6), and Q (7, –1).

Let (x1, y1) = (–5, –6) and (x2, y2) = (7, –1). Then x1 = –5, x2 = 7, y1 = –6 and y2 = –1.

Substitute the values x1 = –5, x2 = 7, y1 = –6 and y2 = –1 in the distance formula to find the distance as follows.

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d(P.Q) x-(y;- y.) 7-(-5)+(-1-(-6) =(7+5)+(-1+6) 12)+(5) (Distance formula)

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Step 2

Simplify the function as follows.

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d(P.g) 144+25 = V169 13 Thus, the distance between the points is 13.

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Step 3

(b)

The coordinates of the midpoint M of the line...

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2 2

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