1A 8A H 2A 3A 4A 5A 6A 7A He B CN O F Ne Li Be Na Mg 3B 4B 58 6B 7B 881B 28 AI Si PSCI Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Zr ND Mo Te Ru Rh Pd Rg Cd In Sn Sb TeXe Cs Ba La Hf Ta w Re Os Ir Pt Au Hg T Pb Bi Po At Rn Fr Ra Ac Rf Ha Ce Pr Nd Pm Sm Eu 6d Tb Dy Ho Er Im Yb Lu Th Pa UNp Pu Am Cm Bk Cf Es Fm Md No Lr Considering only ions with charges of +1, +2, -1 and -2, or neutral atoms, give the symbols for 4 species that are isoelectronic with Ar

1A 8A H 2A 3A 4A 5A 6A 7A He B CN O F Ne Li Be Na Mg 3B 4B 58 6B 7B 881B 28 AI Si PSCI Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Zr ND Mo Te Ru Rh Pd Rg Cd In Sn Sb TeXe Cs Ba La Hf Ta w Re Os Ir Pt Au Hg T Pb Bi Po At Rn Fr Ra Ac Rf Ha Ce Pr Nd Pm Sm Eu 6d Tb Dy Ho Er Im Yb Lu Th Pa UNp Pu Am Cm Bk Cf Es Fm Md No Lr Considering only ions with charges of +1, +2, -1 and -2, or neutral atoms, give the symbols for 4 species that are isoelectronic with Ar

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and e xplain the differences between the following terms. a. law and theory b. theory and...

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Define and e xplain the differences between the following terms. a. law and theory b. theory and experiment c. qualitative and quantitative d. hypothesis and theory
A materials engineer has filed for a patent for a new alloy to be used in golf club heads. The composition by mass ranges from 25 to 31% manganese, 6.3 to 7.8% aluminum, 0.65 to 0.85% carbon, and 5.5 to 9.0% chromium, with the remainder being iron. What are the maximum and minimum percentages of iron possible in this alloy? Use Figure 2.12 to snake a prediction about how the density of this alloy would compare with that of iron; justify your prediction.
The early alchemists used to do an experiment in which water was boiled for several days in a sealed glass container. Eventually. some solid residue would appear in die bottom of the flask, which was interpreted to mean that some of the water in the flask had been converted into earth. When Lavoisier repeated this experiment, he found that the water weighed the same before and after heating, and the mass of die flask plus the solid residue equaled the original mass of the flask. Were the alchemists correct? Explain what really happened. (This experiment is described in the article by A. F. Scott in Scientific American, January 1984.)
Copper atoms. (a) What is the average mass of one copper atom? (b) Students in a college computer science class once sued the college because they were asked to calculate the cost of one atom and could not do it. But you are in a chemistry course, and you can do this. (See E. Felsenthal, Wall Street Journal, May 9, 1995.) If the cost of 2.0-mm diameter copper wire (99.9995% pure] is currently 41.70 for 7.0 g, what is the cost of one copper atom?
There are 1.699 1022 atoms in 1.000 g of chlorine. Assume that chlorine atoms are spheres of radius 0.99 and that they are lined up side by side in a 0.5-g sample. How many miles in length is the line of chlorine atoms in the sample?
F2(g)+2e-→2F-(aq) 2.866 O3(g)+2H+(aq)+2e-→O2(g)+H2O(l) 2.076 Co3+(aq)+e-→Co2+(aq) 1.92 H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776 Ce4+(aq)+e-→Ce3+(aq) 1.72 Au+(aq)+e-→Au(s) 1.692 PbO2(s)+4H+(aq)+SO42-(aq)+2e-→PbSO4(s)+2H2O(l) 1.691 MnO4-(aq)+8H+(aq)+5e-→Mn2+(aq)+4H2O(l) 1.507 Au3+(aq)+3e-→Au(s) 1.498 Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36 Cl2(g)+2e-→2Cl-(aq) 1.358 O2(g)+4H+(aq)+4e-→2H2O(l) 1.229 MnO2(s)+4H+(aq)+2e-→Mn2+(aq)+2H2O(l) 1.224 2IO3-(aq)+12H+(aq)+10e-→I2(s)+6H2O(l) 1.195 Br2(l)+2e-→2Br-(aq) 1.066 VO2+(aq)+2H+(aq)+e-→VO2+(aq)+H2O(l) 0.991 HNO2(aq)+H+(aq)+e-→NO(g)+H2O(l) 0.983 NO3-(aq)+4H+(aq)+3e-→NO(g)+2H2O(l) 0.957 2Hg2+(aq)+2e-→Hg22+(aq) 0.92 Hg2+(aq)+2e-→Hg(l) 0.851 Ag+(aq)+e-→Ag(s) 0.800 Hg22+(aq)+2e-→2Hg(l) 0.797 Fe3+(aq)+e-→Fe2+(aq) 0.771 O2(g)+2H+(aq)+2e-→H2O2(aq) 0.695 MnO4-(aq)+2H2O(l)+3e-→MnO2(s)+4OH-(aq) 0.595 I2(s)+2e-→2I-(aq) 0.536 Cu+(aq)+e-→Cu(s) 0.521 O2(g)+2H2O(l)+4e-→4OH-(aq)…
Am I right? Calculate the mass percentage of water in the hydrate. Show the calculations. Sample 1 : 60.87% Mass of hydrate : 0.46g Mas of water : 0.28g Mass percentage of water in the hydrate = 0.28g/0.46g x 100 = 60.87% Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish 1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt 1.70g 1.94g 1.80g - Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1…
Mass of crucible and cover 12.73g 2. Mass of crucible, cover, and sample 24.11g 3. Mass of original sample 24.11- 12.73g= 11.97g 4. Mass of crucible, cover, and sample after 1st heating 20.01g 6. Mass of crucible, cover, and sample after 2nd heating (assume that this step was done) 19.98 g 7. Total mass lost by sample during heating what is the percentage of water in the sample? and what is the total mass lost by the sample?
Calculate the mass of Cu in g from 8.20 kg CuFeS2
8) Elements A and Q form two compounds. The ratio (mass Q)/(mass A) for compound one is 0.271 and ratio (mass Q)/(mass A) for compound two is 0.362. If compound one has the chemical formula AQ, what is the chemical formula for compound two? a) AQ3 b) A2Q3 c) AQ2 d) A3Q4
Ag+(aq)+e-→Ag(s) 0.800 Al3+(aq)+3e-→Al(s) -1.676 Au+(aq)+e-→Au(s) 1.692 Au3+(aq)+3e-→Au(s) 1.498 Ba2+(aq)+2e-→Ba(s) -2.912 Be2+(aq)+2e-→Be(s) -1.847 Br2(l)+2e-→2Br-(aq) 1.066 Ca2+(aq)+2e-→Ca(s) -2.868 Cd2+(aq)+2e-→Cd(s) -0.403 Ce4+(aq)+e-→Ce3+(aq) 1.72 Cl2(g)+2e-→2Cl-(aq) 1.358 Co2+(aq)+2e-→Co(s) -0.28 Co3+(aq)+e-→Co2+(aq) 1.92 Cr2+(aq)+2e-→Cr(s) -0.913 Cr3+(aq)+e-→Cr2+(aq) -0.407 Cr3+(aq)+3e-→Cr(s) -0.744 CrO42-(aq)+4H2O(l)+3e-→Cr(OH)3(s)+5OH-(aq) -0.13 Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36 Cu+(aq)+e-→Cu(s) 0.521 Cu2+(aq)+e-→Cu+(aq) 0.153 Cu2+(aq)+2e-→Cu(s) 0.342 F2(g)+2e-→2F-(aq) 2.866 Fe2+(aq)+2e-→Fe(s) -0.447 Fe3+(aq)+e-→Fe2+(aq) 0.771 Fe3+(aq)+3e-→Fe(s) -0.037 2H+(aq)+2e-→H2(g) 0.000 2H2O(l)+2e-→H2(g)+2OH-(aq) -0.828 H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776 Hg2+(aq)+2e-→Hg(l) 0.851 2Hg2+(aq)+2e-→Hg22+(aq) 0.92 Hg22+(aq)+2e-→2Hg(l) 0.797 I2(s)+2e-→2I-(aq) 0.536…
Bromine is used to prepare the pesticide methyl bromide andflame retardants for plastic electronic housings. It is recoveredfrom seawater, underground brines, and the Dead Sea. The aver-age concentrations of bromine in seawater (d=1.024 g/mL) andthe Dead Sea (d=1.22 g/mL) are 0.065 g/L and 0.50 g/L, re-spectively. What is the mass ratio of bromine in the Dead Sea tothat in seawater?