1A8AH 2A3A 4A 5A 6A7A HeLi BeB CNOF NeNa Mg 3B 4B 5B 6B 7Br 881B 2B A1 SiS C ArK Ca Sc Ti VCr Mn Fe Co Ni Cu Zn Ga Ge As Se Br KrRb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I XeCs Ba La Hf Ta W ReOs Ir Pt Au Hg TI Pb Bi Po At RnFr Ra Ac RT HaCe Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb LuTh Pa UNp Pu Am Cm Bk Cf Es Fm Md No Lra. What is the element with an electron configuration of 1s 2s 2p° 3s23p° 4s 3d° ?b. What is the element with an electron configuration of 1s2s 2p° 3s?? 1A8AH 2A3A 4A 5A 6A 7A HeLi BeBCNOF NeNa Mg 3B 4B 58 6B 7Br 8818 2B Al Si PS CI ArK Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br KrRb Sr Y Z ND Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te XeCs Ba La Hf Ta WREOS Ir Pt Au Hg TI Pb BI Po At RnFr Ra Ac Rf HaCe Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb LuTh Pa UNp Pu Am Cm Bk Cf ES Fm Md No Lra. The element with an electron configuration of 1s22s² 2p°3s 3p 4s 3d° is in groupb. The element with an electron configuration of 1s 2s 2p°3s 3p° 4s 3d" 4p is in groupand periodand period

The electronic configuration helps us to predict the group and the period of an element in the…

1A 8A H 2A 3A 4A 5A 6A 7A He Li Be BCN0 F Ne Na Mg 3B 4B 5B 6B 7B 88 - 18 2B AI Si P S CI Ar K Ca Sc Ti V Cr Mn Fe Co NiCu Zn Ga Ge As Se Br Kr Rb Sr Y 2r Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe Cs Ba La Hf Ta W Re Os Ir Pt Au Hg TI Pb Bi Po At Rn ** Fr Ra Ac Rf Ha Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa UNp Pu Am Cm Bk Cf Es Fm Md No Lr t is the element with an electron configuration of 1s 2s²2p° 3s² 3p 4 .

1A 8A H 2A 3A 4A 5A 6A 7A He Li Be BCN0 F Ne Na Mg 3B 4B 5B 6B 7B 88 - 18 2B AI Si P S CI Ar K Ca Sc Ti V Cr Mn Fe Co NiCu Zn Ga Ge As Se Br Kr Rb Sr Y 2r Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe Cs Ba La Hf Ta W Re Os Ir Pt Au Hg TI Pb Bi Po At Rn ** Fr Ra Ac Rf Ha Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa UNp Pu Am Cm Bk Cf Es Fm Md No Lr t is the element with an electron configuration of 1s 2s²2p° 3s² 3p 4 .

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and e xplain the differences between the following terms. a. law and theory b. theory and...

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Define and e xplain the differences between the following terms. a. law and theory b. theory and experiment c. qualitative and quantitative d. hypothesis and theory
A materials engineer has filed for a patent for a new alloy to be used in golf club heads. The composition by mass ranges from 25 to 31% manganese, 6.3 to 7.8% aluminum, 0.65 to 0.85% carbon, and 5.5 to 9.0% chromium, with the remainder being iron. What are the maximum and minimum percentages of iron possible in this alloy? Use Figure 2.12 to snake a prediction about how the density of this alloy would compare with that of iron; justify your prediction.
You take three compounds, each consisting of two elements (X, Y. and/or Z), and decompose them to their respective elements. To determine the relative masses of X, Y. and Z. you collect and weigh the elements, obtaining the following data: Elements in Compound Masses of Elements 1. X and Y X = 0.4 g, Y = 4.2 g 2. Y and Z Y = 1.4 g, Z = 1.0 g 3. X and Y X = 2.0 g, Y = 7.0 g a. What are the assumptions needed to solve this problem? b. What are the relative masses of X, Y. and Z? c. What are the chemical formulas of the three compounds? d. If you decompose 21 g of compound XY, how much of each element is present?
Consider the following data for three binary compounds of hydrogen and nitrogen: %H (by Mass) %N (by Mass) I 17.75 82.25 II 12.58 87.42 III 2.34 97.66 When 1.00 L of each gaseous compound is decomposed to its elements, the following volumes of H2(g) and N2(g) are obtained: H2(L) N2(L) I 1.50 0.50 II 2.00 1.00 III 0.50 1.50 Use these data to determine the molecular formulas of compounds I, II, and III and to determine the relative values for the atomic masses of hydrogen and nitrogen.
Copper atoms. (a) What is the average mass of one copper atom? (b) Students in a college computer science class once sued the college because they were asked to calculate the cost of one atom and could not do it. But you are in a chemistry course, and you can do this. (See E. Felsenthal, Wall Street Journal, May 9, 1995.) If the cost of 2.0-mm diameter copper wire (99.9995% pure] is currently 41.70 for 7.0 g, what is the cost of one copper atom?
There are 1.699 1022 atoms in 1.000 g of chlorine. Assume that chlorine atoms are spheres of radius 0.99 and that they are lined up side by side in a 0.5-g sample. How many miles in length is the line of chlorine atoms in the sample?
Am I right? Calculate the mass percentage of water in the hydrate. Show the calculations. Sample 1 : 60.87% Mass of hydrate : 0.46g Mas of water : 0.28g Mass percentage of water in the hydrate = 0.28g/0.46g x 100 = 60.87% Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish 1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt 1.70g 1.94g 1.80g - Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1…
Calculate the mass of Cu in g from 8.20 kg CuFeS2
Ecell Mg‎2+(aq) + 2 e- -> Mg(s) Mg2 + |M‎g = - 2.372 Sn4‎+(aq) + 2 e- -> S‎n2+(aq) Sn2 + , Sn4 + |Pt = + 0.154 Cl‎2 (g) + 2 e- -> 2 Cl-(‎aq Cl-| Cl2 |Pt = +1.‎36 Whic‎h of the follo‎wing is best reduc‎ing ag‎ent for Cl2(g)? a. Mg‎(s) b. Mg‎2+(aq c. Sn4‎+(aq) d. Sn2‎+(aq
A nail is coated with a 5.49E-2 cm thick layer of zinc. The surface area of the nail is 8.27 cm2. The density of zinc is 7.13 g/cm3. How many zinc atoms are used in the coating?
F2(g)+2e-→2F-(aq) 2.866 O3(g)+2H+(aq)+2e-→O2(g)+H2O(l) 2.076 Co3+(aq)+e-→Co2+(aq) 1.92 H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776 Ce4+(aq)+e-→Ce3+(aq) 1.72 Au+(aq)+e-→Au(s) 1.692 PbO2(s)+4H+(aq)+SO42-(aq)+2e-→PbSO4(s)+2H2O(l) 1.691 MnO4-(aq)+8H+(aq)+5e-→Mn2+(aq)+4H2O(l) 1.507 Au3+(aq)+3e-→Au(s) 1.498 Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36 Cl2(g)+2e-→2Cl-(aq) 1.358 O2(g)+4H+(aq)+4e-→2H2O(l) 1.229 MnO2(s)+4H+(aq)+2e-→Mn2+(aq)+2H2O(l) 1.224 2IO3-(aq)+12H+(aq)+10e-→I2(s)+6H2O(l) 1.195 Br2(l)+2e-→2Br-(aq) 1.066 VO2+(aq)+2H+(aq)+e-→VO2+(aq)+H2O(l) 0.991 HNO2(aq)+H+(aq)+e-→NO(g)+H2O(l) 0.983 NO3-(aq)+4H+(aq)+3e-→NO(g)+2H2O(l) 0.957 2Hg2+(aq)+2e-→Hg22+(aq) 0.92 Hg2+(aq)+2e-→Hg(l) 0.851 Ag+(aq)+e-→Ag(s) 0.800 Hg22+(aq)+2e-→2Hg(l) 0.797 Fe3+(aq)+e-→Fe2+(aq) 0.771 O2(g)+2H+(aq)+2e-→H2O2(aq) 0.695 MnO4-(aq)+2H2O(l)+3e-→MnO2(s)+4OH-(aq) 0.595 I2(s)+2e-→2I-(aq) 0.536 Cu+(aq)+e-→Cu(s) 0.521 O2(g)+2H2O(l)+4e-→4OH-(aq)…
8) Elements A and Q form two compounds. The ratio (mass Q)/(mass A) for compound one is 0.271 and ratio (mass Q)/(mass A) for compound two is 0.362. If compound one has the chemical formula AQ, what is the chemical formula for compound two? a) AQ3 b) A2Q3 c) AQ2 d) A3Q4