1A 8A H 2A 3A 4A 5A 6A 7A He Li Be BCNO F Ne Na Mg 3B 4B 5B 6B 7B 8B 1B 2B AI Si P S CI Ar K Ca Sc TiV Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe Cs Ba La Hf Ta W Re Os Ir Pt Au Hg TI Pb Bi Po At Rn Fr Ra Ac Rf Ha Ce Pr NdPm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa UNp Pu Am Cm Bk Cf Es Fm Md No Lr (1) What is the name of the element with a valence electron configuration of 3s'? (2) What is the name of the element with a valence electron configuration of 4s24p1? Submit Answer Try Another Version 5 item attempts remaining

1A 8A H 2A 3A 4A 5A 6A 7A He Li Be BCNO F Ne Na Mg 3B 4B 5B 6B 7B 8B 1B 2B AI Si P S CI Ar K Ca Sc TiV Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe Cs Ba La Hf Ta W Re Os Ir Pt Au Hg TI Pb Bi Po At Rn Fr Ra Ac Rf Ha Ce Pr NdPm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa UNp Pu Am Cm Bk Cf Es Fm Md No Lr (1) What is the name of the element with a valence electron configuration of 3s'? (2) What is the name of the element with a valence electron configuration of 4s24p1? Submit Answer Try Another Version 5 item attempts remaining

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter1: The Nature Of Chemistry

Section: Chapter Questions

Problem 88QRT

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A materials engineer has filed for a patent for a new alloy to be used in golf club heads. The composition by mass ranges from 25 to 31% manganese, 6.3 to 7.8% aluminum, 0.65 to 0.85% carbon, and 5.5 to 9.0% chromium, with the remainder being iron. What are the maximum and minimum percentages of iron possible in this alloy? Use Figure 2.12 to snake a prediction about how the density of this alloy would compare with that of iron; justify your prediction.
Bromine is used to prepare the pesticide methyl bromide andflame retardants for plastic electronic housings. It is recoveredfrom seawater, underground brines, and the Dead Sea. The aver-age concentrations of bromine in seawater (d=1.024 g/mL) andthe Dead Sea (d=1.22 g/mL) are 0.065 g/L and 0.50 g/L, re-spectively. What is the mass ratio of bromine in the Dead Sea tothat in seawater?
A piece of copper has a volume of 560 L what is mass of sample in grams. For the problem it gives me 1cm^3Cu = 9g CU 9.5 x 10^21 atoms Cu= 1 Cu 1KG =1000g 1cm^3 =1mL 1L=1000cm^3 It basically wants me to write out the conversions correctly i just dont know which ones to use. Thank you so much for the help I really appreciate it.
Am I right? Calculate the mass percentage of water in the hydrate. Show the calculations. Sample 1 : 60.87% Mass of hydrate : 0.46g Mas of water : 0.28g Mass percentage of water in the hydrate = 0.28g/0.46g x 100 = 60.87% Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish 1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt 1.70g 1.94g 1.80g - Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1…
1 A)5.63,4.42,2.50,or 1.25 1 B)L,g,mol,or kg 2 A)129,0.109,86.0,or 57.5 2 B)g,mol,L,or mg
Ag+(aq)+e-→Ag(s) 0.800 Al3+(aq)+3e-→Al(s) -1.676 Au+(aq)+e-→Au(s) 1.692 Au3+(aq)+3e-→Au(s) 1.498 Ba2+(aq)+2e-→Ba(s) -2.912 Be2+(aq)+2e-→Be(s) -1.847 Br2(l)+2e-→2Br-(aq) 1.066 Ca2+(aq)+2e-→Ca(s) -2.868 Cd2+(aq)+2e-→Cd(s) -0.403 Ce4+(aq)+e-→Ce3+(aq) 1.72 Cl2(g)+2e-→2Cl-(aq) 1.358 Co2+(aq)+2e-→Co(s) -0.28 Co3+(aq)+e-→Co2+(aq) 1.92 Cr2+(aq)+2e-→Cr(s) -0.913 Cr3+(aq)+e-→Cr2+(aq) -0.407 Cr3+(aq)+3e-→Cr(s) -0.744 CrO42-(aq)+4H2O(l)+3e-→Cr(OH)3(s)+5OH-(aq) -0.13 Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36 Cu+(aq)+e-→Cu(s) 0.521 Cu2+(aq)+e-→Cu+(aq) 0.153 Cu2+(aq)+2e-→Cu(s) 0.342 F2(g)+2e-→2F-(aq) 2.866 Fe2+(aq)+2e-→Fe(s) -0.447 Fe3+(aq)+e-→Fe2+(aq) 0.771 Fe3+(aq)+3e-→Fe(s) -0.037 2H+(aq)+2e-→H2(g) 0.000 2H2O(l)+2e-→H2(g)+2OH-(aq) -0.828 H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776 Hg2+(aq)+2e-→Hg(l) 0.851 2Hg2+(aq)+2e-→Hg22+(aq) 0.92 Hg22+(aq)+2e-→2Hg(l) 0.797 I2(s)+2e-→2I-(aq) 0.536…
The density of Neon (Ne) at a specific temperature and pressure is 3.21 x 10-5 lb/in3. Calculate the volume of 1.2 x 108 Ne atoms, in cm3, under these conditions. 1000 lb = 453.6 g 1 inch = 2.54 cm
F2(g)+2e-→2F-(aq) 2.866 O3(g)+2H+(aq)+2e-→O2(g)+H2O(l) 2.076 Co3+(aq)+e-→Co2+(aq) 1.92 H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776 Ce4+(aq)+e-→Ce3+(aq) 1.72 Au+(aq)+e-→Au(s) 1.692 PbO2(s)+4H+(aq)+SO42-(aq)+2e-→PbSO4(s)+2H2O(l) 1.691 MnO4-(aq)+8H+(aq)+5e-→Mn2+(aq)+4H2O(l) 1.507 Au3+(aq)+3e-→Au(s) 1.498 Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36 Cl2(g)+2e-→2Cl-(aq) 1.358 O2(g)+4H+(aq)+4e-→2H2O(l) 1.229 MnO2(s)+4H+(aq)+2e-→Mn2+(aq)+2H2O(l) 1.224 2IO3-(aq)+12H+(aq)+10e-→I2(s)+6H2O(l) 1.195 Br2(l)+2e-→2Br-(aq) 1.066 VO2+(aq)+2H+(aq)+e-→VO2+(aq)+H2O(l) 0.991 HNO2(aq)+H+(aq)+e-→NO(g)+H2O(l) 0.983 NO3-(aq)+4H+(aq)+3e-→NO(g)+2H2O(l) 0.957 2Hg2+(aq)+2e-→Hg22+(aq) 0.92 Hg2+(aq)+2e-→Hg(l) 0.851 Ag+(aq)+e-→Ag(s) 0.800 Hg22+(aq)+2e-→2Hg(l) 0.797 Fe3+(aq)+e-→Fe2+(aq) 0.771 O2(g)+2H+(aq)+2e-→H2O2(aq) 0.695 MnO4-(aq)+2H2O(l)+3e-→MnO2(s)+4OH-(aq) 0.595 I2(s)+2e-→2I-(aq) 0.536 Cu+(aq)+e-→Cu(s) 0.521 O2(g)+2H2O(l)+4e-→4OH-(aq)…
A cube of an unknown metal measures 1.61 mm on one side. The mass of the cube is 36 mg. Which of the following is most likely the unknown metal? d(Nb) = 8.57 g/mL d(Rh) = 12.41 g/mL d(Sn) = 7.31 g/mL d(V) = 6.11 g/mL d(Zn) = 7.13 g/mL Group of answer choices niobium rhodium tin vanadium zinc
a.) I=R, II = Rb.) I = S, I = Rc.) I=R, II = Sd.) I= S, I = S
There are 1.699 x 1022 atoms in 1.000 g of chlorine. Assume that chlorine atoms are spheres of radius 0.099 nm and that they are lined up side by side in a 0.50 g sample. How many miles in length is the line of chlorine atoms in the sample? 1 mi = 1609 m
Naturally occurring cobalt consists of only one isotope, 59Co , whose relative atomic mass is 58.9332. A synthetic radioactive isotope of cobalt, 60Co , relative atomic mass 59.9338, is used in radiation therapy for cancer. A 1.7320 g sample of cobalt has an apparent "atomic mass" of 58.9901. Find the mass of 60Co in this sample. Express your answer with the appropriate units. Express no of atoms using four significant figures 21.899 g Cr 46.347 gS 12.360 g Pt 96.471 g Sn