1A8AH 2A3A 4A 5A 6A 7A HeLi BeB C NO F NeNa Mg 3B 4B 5B 6B 7B 8B H 1B 2B Al Si P S CI ArK Ca sc Ti v Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br KrRb Sr Y zr Nb Mo Tc Ru Rh Pd Ag cd In Sn Sb Te I XeCs Ba La Hf Ta w Re Os Ir Pt Au Hg TI Pb Bi Po At RnFr Ra Ac Rf Ha**Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb LuTh Pa U Np Pu Am Cm Bk Cf Es Fm Md No LrConsidering only ions with charges of +1, +2, -1 and -2, or neutral atoms, give the symbols for 4 species that are isoelectronic with Ar.

Four atoms are isoelectronic with Ar with charge +1 , +2 , -1 , -2 * isoelectronic means they have…

1A 8A H 2A 3A 4A SA 6A 7A He Li Be BC NO F Ne Na Mg 38 4B 5B 68 7B - 8B - 1B 28 AI si P S CI Ar K Ca sc Ti vCr Mn Fe Co Ni cu Zn Ga Ge As Se Br Kr Rb Sr v zr Nb Mo Tc Ru Rh Pd Ag ca In Sn Sb Te 1 Xe Cs Ba La Hf Ta w Re Os Ir Pt Au Hg TI Pb Bi Po At Rn Fr Ra Ac Rr Ha Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cr Es Fm Md No Lr Considering only ions with charges of +1, +2, -1 and -2, or neutral atoms, give the symbols for 4 species that are isoelectronic with Ar.

1A 8A H 2A 3A 4A SA 6A 7A He Li Be BC NO F Ne Na Mg 38 4B 5B 68 7B - 8B - 1B 28 AI si P S CI Ar K Ca sc Ti vCr Mn Fe Co Ni cu Zn Ga Ge As Se Br Kr Rb Sr v zr Nb Mo Tc Ru Rh Pd Ag ca In Sn Sb Te 1 Xe Cs Ba La Hf Ta w Re Os Ir Pt Au Hg TI Pb Bi Po At Rn Fr Ra Ac Rr Ha Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cr Es Fm Md No Lr Considering only ions with charges of +1, +2, -1 and -2, or neutral atoms, give the symbols for 4 species that are isoelectronic with Ar.

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and e xplain the differences between the following terms. a. law and theory b. theory and...

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A materials engineer has filed for a patent for a new alloy to be used in golf club heads. The composition by mass ranges from 25 to 31% manganese, 6.3 to 7.8% aluminum, 0.65 to 0.85% carbon, and 5.5 to 9.0% chromium, with the remainder being iron. What are the maximum and minimum percentages of iron possible in this alloy? Use Figure 2.12 to snake a prediction about how the density of this alloy would compare with that of iron; justify your prediction.
Copper atoms. (a) What is the average mass of one copper atom? (b) Students in a college computer science class once sued the college because they were asked to calculate the cost of one atom and could not do it. But you are in a chemistry course, and you can do this. (See E. Felsenthal, Wall Street Journal, May 9, 1995.) If the cost of 2.0-mm diameter copper wire (99.9995% pure] is currently 41.70 for 7.0 g, what is the cost of one copper atom?
Define and e xplain the differences between the following terms. a. law and theory b. theory and experiment c. qualitative and quantitative d. hypothesis and theory
The early alchemists used to do an experiment in which water was boiled for several days in a sealed glass container. Eventually. some solid residue would appear in die bottom of the flask, which was interpreted to mean that some of the water in the flask had been converted into earth. When Lavoisier repeated this experiment, he found that the water weighed the same before and after heating, and the mass of die flask plus the solid residue equaled the original mass of the flask. Were the alchemists correct? Explain what really happened. (This experiment is described in the article by A. F. Scott in Scientific American, January 1984.)
There are 1.699 1022 atoms in 1.000 g of chlorine. Assume that chlorine atoms are spheres of radius 0.99 and that they are lined up side by side in a 0.5-g sample. How many miles in length is the line of chlorine atoms in the sample?
Consider the following data for three binary compounds of hydrogen and nitrogen: %H (by Mass) %N (by Mass) I 17.75 82.25 II 12.58 87.42 III 2.34 97.66 When 1.00 L of each gaseous compound is decomposed to its elements, the following volumes of H2(g) and N2(g) are obtained: H2(L) N2(L) I 1.50 0.50 II 2.00 1.00 III 0.50 1.50 Use these data to determine the molecular formulas of compounds I, II, and III and to determine the relative values for the atomic masses of hydrogen and nitrogen.
You take three compounds, each consisting of two elements (X, Y. and/or Z), and decompose them to their respective elements. To determine the relative masses of X, Y. and Z. you collect and weigh the elements, obtaining the following data: Elements in Compound Masses of Elements 1. X and Y X = 0.4 g, Y = 4.2 g 2. Y and Z Y = 1.4 g, Z = 1.0 g 3. X and Y X = 2.0 g, Y = 7.0 g a. What are the assumptions needed to solve this problem? b. What are the relative masses of X, Y. and Z? c. What are the chemical formulas of the three compounds? d. If you decompose 21 g of compound XY, how much of each element is present?
Classify the following as compounds or elements: a silver bromide used in photography; b calcium carbonate limestone; c sodium hydroxide lye; d uranium; e tin; f titanium.
a.) I=R, II = Rb.) I = S, I = Rc.) I=R, II = Sd.) I= S, I = S
Am I right? Calculate the mass percentage of water in the hydrate. Show the calculations. Sample 1 : 60.87% Mass of hydrate : 0.46g Mas of water : 0.28g Mass percentage of water in the hydrate = 0.28g/0.46g x 100 = 60.87% Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish 1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt 1.70g 1.94g 1.80g - Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1…
There are 1.699 x 1022 atoms in 1.000 g of chlorine. Assume that chlorine atoms are spheres of radius 0.099 nm and that they are lined up side by side in a 0.50 g sample. How many miles in length is the line of chlorine atoms in the sample? 1 mi = 1609 m
Mass of crucible and cover 12.73g 2. Mass of crucible, cover, and sample 24.11g 3. Mass of original sample 24.11- 12.73g= 11.97g 4. Mass of crucible, cover, and sample after 1st heating 20.01g 6. Mass of crucible, cover, and sample after 2nd heating (assume that this step was done) 19.98 g 7. Total mass lost by sample during heating what is the percentage of water in the sample? and what is the total mass lost by the sample?