Asked Oct 11, 2019

1a.) what is the solubility of Hg2CO3 in pure water in grams/liter, if the Ksp=89x10^-17

b.) If your target goal is to have no more than a concentration of CO3-2 dissovled in water equal to 75ppb, what concentration of HG+1 needs to be in the solution?

c.) how many grams of Hg(NO3) would you need to put in 2.5 liters of water to produce this concetration of mecury ion?


Expert Answer

Step 1

(a)The solubility of mercury carbonate in pure water can be calculated as


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Given, K8.9x1017 Solubility of Hg,CO, =Smol/L Hg CO, Hgco K-Hco] S= =8.9x107 -9.43x10mol/L 1mol of Hg,CO, 461.188g/mol S 9.43x10 x461.188 g/L 4.3x10 g/L Solubility of Hg,CO,-4.3x10 g/L

Step 2

(b)The concentration of mercuric ions needed...


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concentrati on of Co, dissolvedin water-75ppb 75ppb CO-75x10 ppm-75x10mg/LCo 75x10 mmol/L of co 60 Hg,CO 2Hg co mol 2mol mol 75x10 mol CO=2x 75x103) Hg 60 60 75x10200.59 mg/L Hg =2 x 60 501.4x103mg/L 501.4 ppb Hg


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