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291d

Question

In the figure particles with charges q1 = +6e and q2 = -14e are fixed in place with a separation of d = 18.6 cm. With V = 0 at infinity, what are the finite (a) positive and (b) negative values of x at which the net electric potential on the x axis is zero?

 

2
91
d
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2 91 d

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Step 1

Given,

Charge 1, q,6e
Charge 2, q-14e
Seperation between charge, d 18.6 cm
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Charge 1, q,6e Charge 2, q-14e Seperation between charge, d 18.6 cm

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Step 2

Potential is scalar quantity, the electric potential due to the system of charge can be found by adding potential due to individual charges,

1
Σ1
= 4
4TE
where, qis chargeand ris the distancefrom charge
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1 Σ1 = 4 4TE where, qis chargeand ris the distancefrom charge

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Step 3

Charge 1 at origin and charge 2 is at distance d on the x-axis.

Assume a point P on the x-axis at...

1
V
4ле, х
4те, (х - а)
[:и, -0]
1
0 =
4те, х
4ле, (х - d)
afterrearranging
бе
-d
9,а
бе - 14е
9. + 9.
х%3 -—d
4
3(18.6сm) -13.95сm
4
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1 V 4ле, х 4те, (х - а) [:и, -0] 1 0 = 4те, х 4ле, (х - d) afterrearranging бе -d 9,а бе - 14е 9. + 9. х%3 -—d 4 3(18.6сm) -13.95сm 4

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Physics

Electrostatic Potential and Capacitance

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