Question
Asked Sep 28, 2019
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Figure (a) shows three plastic sheets that are large, parallel, and uniformly charged. Figure (b) gives the component of the net electric field along an x axis through the sheets. The scale of the vertical axis is set by Es = 9.0 × 105 N/C. What is the ratio of the charge density on sheet 3 to that on sheet 2?

2
(a)
(b)
E(10 N/C)
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2 (a) (b) E(10 N/C)

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Step 1

From the figure (b), it can be seen that the net electric field at right side of sheet 3 is zero. For this to happen, there are three possibilities.

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E E-E 0 E- E E0 -E+EE0 .D

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Step 2

The electric field between sheet 2 and 3 is given as 54.0×105 N/C. It means,

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E+E 54.0x10'N/C The electric field between sheet 1 and 2 is given as 18.0x10^N/C. It means E+E 18.0x 10N/C Subtract equation (II)from() E2+E-E-E 54.0 x 10'N/C -18.0 x 10 N/C E-E 36.0x10'N/C

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Step 3

Use the above relation ...

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E+36.0x10 N/C 0 E-36.0x 10 N/C

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